Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 16, Problem 16.11P
To determine
Find the gross allowable load
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Students have asked these similar questions
A circular footing with a 1.5 m diameter is to be
constructed 1.22 m
below the ground surface. The subsoil consists of
a uniform deposit
of dense soil having the following strength
parameters:
Angle of Friction = 250 Nc = 24.1 Nq = 13.1 Ny = 9.1
Cohesion = 48 kN/m2
Unit weight of soil = 20.12 kN/m2
The groundwater table is at a great depth and its
effect can be
ignored.
Determine the following:
a) Ultimate bearing Capacity of the soil
Ex1: A footing is uniformly loaded with q = 100 kN/m² as shown in the figure.
Compute the vertical stress increments under Points A, B, and C at z = 10 m.
By
13.5
Footing
12m
Use Vertical stress Increment
under corner of rectangular
footing
7
(Plane view)
6
Q: VERTICAL STRESS INCREMENT UNDER CORNER OF
RECTANGULAR FOOTING
Ex1: A footing is uniformly loaded with q = 100 kN/m2 as shown in the figure.
Compute the vertical stress increments under Points A, B, and C at z = 10 m.
13.5 m
7.0 m
Footing
12 m
(Plane view)
6.0 m
Chapter 16 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 16 - A continuous footing is shown in Figure 16.17....Ch. 16 - Refer to Problem 16.1. If a square footing with...Ch. 16 - Redo Problem 16.1 with the following: = 115...Ch. 16 - Redo Problem 16.1 with the following: = 16.5...Ch. 16 - Redo Problem 16.1 using the modified general...Ch. 16 - Redo Problem 16.2 using the modified general...Ch. 16 - Redo Problem 16.3 using the modified general...Ch. 16 - Redo Problem 16.4 using the modified general...Ch. 16 - Prob. 16.9PCh. 16 - If the water table in Problem 16.9 drops down to...
Ch. 16 - Prob. 16.11PCh. 16 - A square footing is subjected to an inclined load...Ch. 16 - A square footing (B B) must carry a gross...Ch. 16 - Redo Problem 16.13 with the following data: gross...Ch. 16 - Refer to Problem 16.13. Design the size of the...Ch. 16 - Prob. 16.16PCh. 16 - Prob. 16.17PCh. 16 - Refer to the footing in Problem 16.16. Determine...Ch. 16 - Figure 16.21 shows a continuous foundation with a...Ch. 16 - The following table shows the boring log at a site...
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- Example 24.31. Determine the ultimate net bearing capacity of the circular footing shown in Fig. 24.33. Also, compute the change in ultimate net bearing capacity, if the entire region is flooded, due to which the ground water level reaches ground level. 1.5 m -2 m Clay Cu = 48 kPa $ = 0° y = 1.8 g/cc No = 5.7 3.5 m %3D W.T.arrow_forwardQuiz-2: For the strip footing shown. Calculate the reduction percentage in the bearing capacity of the soil profile when the groundwater rises to the footing base level. Use Meyerhof's equation P = 723 kN/m 0.5 m Yt = 17.0 kN/m3 B = 3.0 m Pure Sand Ywet 18.0 kN/m3 5.9 m Ø = 36.0° W.T. Ysat = 18.0 kN/m3arrow_forward2. A square footing is shown in Figure 16.20. Determine the gross allowable load, Qall, that the footing can carry. Use Terzaghi's equation for general shear failure (F, = 3). Given: y = 105 lb/ft, Yat = 118 lb/ft, c' 0, = 35°, B = 5 ft, D; = 4 ft, and h = 2 ft. Unit weight of soil = y Groundwater table Yat B Figure 16.20arrow_forward
- A square footing 3 m x 3 m is supporting an axial load of 650 kN. The weight of the soil is aasumed to be 17.32 kN/m^3. Compute the vertical stress increment due to this load at a depth of 1.5 m below the center of the footing using the approximate method. a. 51.46 kPa b. 32.10 kPa c. 76.54 kPa d. 50.56 kPaarrow_forwardExl: A footing is uniformly loaded with q = 100 kN/m² as shown in the figure. Compute the vertical stress increments under Points A, B, at z = 10 m. 13.5 m 7.0 m Footing 12 m (Plane view) 6.0 marrow_forwardQ- Determine the width of strip footing to carry a load of 750 kN/m at a depth of 1.6 m in a c-o soil having unit weight of 18 kN/m² and c = 20 kN/m², p=25. Take FOS = 3 and for p=25. (Assume general shear failure) No = 25.1, N₁ = 12.7 and Ny=9.7arrow_forward
- A square footing is shown in Fig. 16.21. Determine the safe gross load (factor of safety of 3) that can carry. 0.5 m 0.5 m 1.2 m Y = 16 kN/m³ c' = 0 Fig. 16.21 o'= 32° Groundwater table Ysat 19.5 kN/m³arrow_forwardQ2. a) A 2 mx 2 m square footing is subjected to an axial load of 600 kN and a bending moment of 180 kNm as appears in Figure 2. The footing is located at 1.2 m deep in a cohesionless soil that has a friction angle of 35° and a saturated unit weight of 18.4 kN/m³. The water table is 2.7 m below the soil surface. Calculate the following, (i) Calculate the eccentricity of the load, (ii) Calculate and draw the soil contact pressure beneath the footing, (iii) Determine the factor of safety of the footing against the bearing capacity (use the general Meyerhof, bearing capacity equation). Assume the soil above water table is saturated. -600 KN /sat = 18.4 kN/m³ 1.2 m c'= 0 kPa, o'= 35° 1.5 m DI. 2 m M = 180 kNm Figure 2arrow_forwardA rectangular footing of size 3 x 2 m is founded at a depth of 1.5 m in a clay stratum of very stiff consistency. A clay layer of medium consistency is located at a depth of 1.5 m (= H) below the bottom of the footing (Fig. Ex. 12.17). The soil parameters of the two clay layers are as follows: Top clay layer: c = 175 kN/m2 Shallow Foundation I: Ultimate Bearing Capacity D, = 1.5 m3 Very stiff clay c, = 175 kN/m? Y = 17.5 kN/m BxL 2x3 m H = 1.5 m Layer 1 Soft clay 2 = 40 kN/m? Y2 = 17.0 kN/m Layer 2 Figure Ex. 12.17arrow_forward
- A footing of size 2m×2m transferring a pressure of 200 kN/m², is placed at a depth of 1.5 m below the ground as shown in the figure (not drawn to the scale). The clay stratum is normally consolidated. The clay has specific gravity of 2.65 and compression index of 0.3. 1.5m 1m 1.5 m 200 kN/m² Silty sand Clay Ya =15kN/m³ Y sat = 18kN/m³ Y sat = 17 kN/m³ GWT $0.5 m Dense sand Considering 2:1 (vertical to horizontal) method of load distribution and Y₁ = 10kN/m³, the primary consolida- tion settlement (in mm, round off to two decimal places) of the clay stratum isarrow_forwardA circular footing is 3.73 m in diameter. The bottom of the footing is 2.68 m below the ground surface. Moist unit weight of soil is 18.36 kn/m3, saturated unit weight is 20.16 kn/m3. Cohesion of soil is 92 kpa. Use Nc = 25.26, Nq= 12.13, Ny= 8.23. If the groundwater table is located at a depth of 1.38 m from the ground surface determine the allowable bearing capacity that the footing can carry. FS = 2.arrow_forward4. A square footing having a dimension of 3 m x 3 m carries an axial load of 1500 kN. The bottom of the footing is 2 m from the ground surface consisting of a layer of sand overlying a 4 m laye of clay. The water table is located 2 m below the ground surface. Dry unit weight of sand = 16.5 kN/m³ Saturated unit weight of clay = 20 kN/m³ Void ratio of clay = 0.80 Liquid limit of clay = 50% a. Compute the increase in vertical pressure. b. Compute the overburden pressure (effective pressure) at the midpoint of clay. c. Compute the primary consolidation settlement. 2m 4 m Sand 1500 KN 3m x 3 m Clay (normally consolidated) Ya 16.5 kN/m² 7sat 20 kNm' e = 0.80 LL = 50 | }arrow_forward
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