The overall formation constant for HgI42- is 1.0x1030. That is, 1.0x1030 = [HgI42-] / [Hg2+] [I-]4 What is the concentration of Hg2+ in 400.0 mL of a solution that was originally 0.016 M Hg2+ and 0.72 M I-? The reaction is  Hg2+ (aq) + 4I- (aq) <----> HgI42- (aq) [Hg2+] = ____________ M

Chemistry: Principles and Reactions
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Chapter15: Complex Ion And Precipitation Equilibria
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The overall formation constant for HgI42- is 1.0x1030. That is,

1.0x1030 = [HgI42-] / [Hg2+] [I-]4

What is the concentration of Hg2+ in 400.0 mL of a solution that was originally 0.016 M Hg2+ and 0.72 M I-? The reaction is 

Hg2+ (aq) + 4I- (aq) <----> HgI42- (aq)

[Hg2+] = ____________ M

 

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