Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Textbook Question
Chapter 19, Problem 19.22SP
Calculate the minimum main plate thickness for the joint of Problem 19.4 so that the plates, which are 7 in wide, will have a capacity equal to the shear capacity of the
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3. An M16 x 2 bolt with a slotted hex nut is used to clamp together two 25 mm steel plates. The joint
is assembled with a size 16 N washer underneath the bolt head. The bolt is a 5.8 class metric grade,
with a proof strength of 380 MPa. The joint is intended to be permanent. Determine a suitable length
for the bolt, rounded up to the nearest standard size in millimeters. Calculate the bolt stiffness, the
elongation of the bolt after the necessary preload is developed, and the bolt torque required to apply
the preload. Assume that coefficients of friction between the bolt, nut, and collar are all ~0.15. For
steel, use E = 207 GPa.
Standard threaded fastener lengths, dimensions of hexagonal nuts, and dimensions of metric plain
washers are provided in the textbook appendices.
Calculate the riveted joints, find its efficiency and draw a suitable sketch.
Thickness of the plates – t, mm is 12
Width of the plates – b, mm is 150
Load – P, kN is 20
Note. Choose a suitable material, determine its tearing stress. Take permissible shearing stress - teta=0.7sigmat ; Permissible crushing stress - sigmac=1.5sigmat ;
Design a single riveted lap joint to connect two mild steel plates, 14.5 mm thick, the joint being designed for maximum efficiency. The allowable stresses are σt = 55 N/mm2 , = 32.5 N/mm2 and σc = 63.5 N/mm2 . Also calculate the minimum force per pitch which will rupture the joint
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
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- The ultimate shearing stress of the rivet used to join plates is 22 ksi. For a factor of safety of 2, calculate the safe shearing resistance of a unit strip of a single-riveted lap joint in which the plate thickness of ¼ in, the pitch joint of ¾ in, and the diameter of the rivet hole is 11/16 inch.arrow_forward4. Determine the design stress for bolts in a cylinder cover where the load is fluctuating due to gas pressure. The maximum load on the bolt is 50 kN and the minimum is 30 kN. The load is unpredict- able and factor of safety is 3. The surface of the bolt is hot rolled and the suface finish factor is 0.9. During a simple tension test and rotating beam test on ductile materials (40 C 8 steel annealed), the following results were obtained : Diameter of specimen =12.5 mm; Yield strength= 240 MPa; Ultimate strength= 450 MPa; Endurance limit = 180 MPa. [Ans. 65.4 MPa]arrow_forward5. A flanged bolt coupling between two shafts carries 12 bolts in a diameter of 18-in. The shafts carry a torque of 50,000 ft.lb. Assuming that this torque is transmitted by shear across the 12 bolts and that these bolts are to be designed for a shear stress of 3,000 psi, what must be the bolt diameter? 18 in Figure 3.6.4 6. A plate is fastened to a fixed member by four 25 – mm diameter rivets arranged ss shown. Compute the maximum and minimum shearing stresses developed? |20 kN 20 kN Figure 3.6.5arrow_forward
- (12) A turnbuckle connects two rods having %-16 UNC threads. The thread friction is 0.2. How much external torque is necessary to stress the rods 500lb if it is assumed that neither rod turns as the turnbuckle is tightened? The mean diameter of the threads is 0.335 in.arrow_forwardA flanged bolt coupling consists of eight – 10mm diameter steelbolts on a bolt circle 500mm in diameter and six – 12mm diametersteel bolts on a concentric bolt circle 350mm in diameter. Whattorque can be applied without exceeding a shearing stress of75MPa in the bolts (Gst = 82GPa)arrow_forwardA 25 mm diameter steel bar is loaded in double shear until failure, the ultimate load is found to be 446 KN. If the allowable stress is to be based on a factor of safety 3, what must be the diameter of a pin designed for an allowable load of 26 KN in single shear be?arrow_forward
- A wooden beam and a steel plate will be attached with three steel bolts. If the plate will be loaded with 120 kN, determine the necessary diameter for the bolts. Assume an ultimate shear stress corresponding to half the ultimate normal stress, for a tool steel, and a factor of safety of 3.25. Sound good material?arrow_forwardIdentify the flange thickness (in mm) of a flange coupling having 6 bolts, that is 10-mm in diameter, with an 80-mm diameter bolt circle, which is used to connect two identical shafts that is 40-mm in diameter. The design shearing stress of the shaft is 20 MPa while the design crushing stress of the flange is 30 MPa.arrow_forwardM16 x 2.0 ISO 5.8 coarse series bolts and nuts clamp a 26-mm-thick steel cover plate to a 6-mm-thick steel flange. Steel washers (Size: 16R) are used under the head of the bolt and also under the nut . Assume E = 207 GPa- (a) Determine a suitable length for the bolt, rounded up to the nearest 5 mm. (b) Determine the bolt stiffness. (c) Determine the stiffness of the members. (d) Determine the stiffness of the joint.arrow_forward
- 4. A solid shaft was made of alloy steel, it was welded to a flat plate by a specific size of fillet weld. If a torque is applied to the shaft, calculate the size of the weld joint. Power Torque Yield stress Shear stress Ultimate stress (Mpa) Compression stress (Mpa) Ductility (%) (kw) (Nm) 1000 (Mpa) 400 (Mpa) 160 280 30 Modulus of Bending Stress Bending Moment Factor of Safety Elasticity (GPa) (Mpa) 220 280 120 4 Modulus of Rigidity (pa) 70 Fracture stress (Mpa) 250arrow_forwardCalculate the maximum tensile stress developed in a 1/4-20 bolt (Major dia = 0.2500" and Root dia = 0.1959"), 3" long, and a head height of 0.1875", if it is subjected to a load of 426 lbs.arrow_forwardDon't attempt wrong .Downvoted for that...A flanged bolt coupling is used to connect a solid shaft 90 mm in diameter to a hollow shaft 100 mm in outsude diameter and 90 mm in inside diameter. If the allowable aring stress in the shafts and the bolts is 60 MPa, how many 10 mm diameter steel bolts must be used on a 200 mm diameter bolt circle so that the coupling will be as strong as the weaker shaft?arrow_forward
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