Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter 19, Problem 50P
(a)
To determine
The maximum amount of heat absorbed by the refrigerator.
(b)
To determine
The heat absorb by the refrigerator.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
(a) Suppose you start a workout on a Stairmaster, producing power at the same rate as climbing 116 stairs per minute. Assuming your mass is 76.0 kg and your efficiency is 20.0, how long will it take for your body temperature to rise 1.00ºCif all other forms of heat transfer in and out of your body are balanced?
(b) Is this consistent with your experience in getting warm while exercising?
(a) Calculate the rate of heat transfer by radiation from a car radiator at 110°C into a 50.0ºC environment, if the radiator has an emissivity of 0.750 and a 1.20-m2 surface area. (b) Is this a significant fraction of the heat transfer by an automobile engine? To answer this, assume a horsepower of 200 hp (1.5 kW) and the efficiency of automobile engines as 25%.
If the air temperature isthe same as the temperature of your skin (about 30°C), your body cannotget rid of heat by transferring it to the air. In that case, it gets ridof the heat by evaporating water (sweat). During bicycling, a typical70 kg person’s body produces energy at a rate of about 500 W due tometabolism, 80% of which is converted to heat. (a) How many kilogramsof water must the person’s body evaporate in an hour to get ridof this heat? The heat of vaporization of water at body temperature is2.42 * 10^6 J/kg. (b) The evaporated water must, of course, be replenished,or the person will dehydrate. How many 750 mL bottles of watermust the bicyclist drink per hour to replenish the lost water? (Recall thatthe mass of a liter of water is 1.0 kg.)
Chapter 19 Solutions
Physics for Scientists and Engineers
Ch. 19 - Prob. 1PCh. 19 - Prob. 2PCh. 19 - Prob. 3PCh. 19 - Prob. 4PCh. 19 - Prob. 5PCh. 19 - Prob. 6PCh. 19 - Prob. 7PCh. 19 - Prob. 8PCh. 19 - Prob. 9PCh. 19 - Prob. 10P
Ch. 19 - Prob. 11PCh. 19 - Prob. 12PCh. 19 - Prob. 13PCh. 19 - Prob. 14PCh. 19 - Prob. 15PCh. 19 - Prob. 16PCh. 19 - Prob. 17PCh. 19 - Prob. 18PCh. 19 - Prob. 19PCh. 19 - Prob. 20PCh. 19 - Prob. 21PCh. 19 - Prob. 22PCh. 19 - Prob. 23PCh. 19 - Prob. 24PCh. 19 - Prob. 25PCh. 19 - Prob. 26PCh. 19 - Prob. 27PCh. 19 - Prob. 28PCh. 19 - Prob. 29PCh. 19 - Prob. 30PCh. 19 - Prob. 31PCh. 19 - Prob. 32PCh. 19 - Prob. 33PCh. 19 - Prob. 34PCh. 19 - Prob. 35PCh. 19 - Prob. 36PCh. 19 - Prob. 37PCh. 19 - Prob. 38PCh. 19 - Prob. 39PCh. 19 - Prob. 40PCh. 19 - Prob. 41PCh. 19 - Prob. 42PCh. 19 - Prob. 43PCh. 19 - Prob. 44PCh. 19 - Prob. 45PCh. 19 - Prob. 46PCh. 19 - Prob. 47PCh. 19 - Prob. 48PCh. 19 - Prob. 49PCh. 19 - Prob. 50PCh. 19 - Prob. 51PCh. 19 - Prob. 52PCh. 19 - Prob. 53PCh. 19 - Prob. 54PCh. 19 - Prob. 55PCh. 19 - Prob. 56PCh. 19 - Prob. 57PCh. 19 - Prob. 58PCh. 19 - Prob. 59PCh. 19 - Prob. 60PCh. 19 - Prob. 61PCh. 19 - Prob. 62PCh. 19 - Prob. 63PCh. 19 - Prob. 64PCh. 19 - Prob. 65PCh. 19 - Prob. 66PCh. 19 - Prob. 67PCh. 19 - Prob. 68PCh. 19 - Prob. 69PCh. 19 - Prob. 70PCh. 19 - Prob. 71PCh. 19 - Prob. 72PCh. 19 - Prob. 73PCh. 19 - Prob. 74PCh. 19 - Prob. 75PCh. 19 - Prob. 76PCh. 19 - Prob. 77PCh. 19 - Prob. 78PCh. 19 - Prob. 79PCh. 19 - Prob. 80PCh. 19 - Prob. 81PCh. 19 - Prob. 82PCh. 19 - Prob. 83PCh. 19 - Prob. 84PCh. 19 - Prob. 85PCh. 19 - Prob. 86PCh. 19 - Prob. 87PCh. 19 - Prob. 88PCh. 19 - Prob. 89P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A 300-W heat pump operates between the ground, whose temperature is 0 , and the interior of a house at 22 . What is the maximum amount of the heat per hour that the heat pump can supply to the house?arrow_forwardMany decisions are made on the basis of the payback period: the time it will take through savings to equal the capital cost of an investment. Acceptable payback times depend upon the business or philosophy one has. For some industries, a payback period is as small as 2 yeas) Suppose you wish to install the extra insulation in the preceding problem. If energy cost $1.00 per million joules and the insulation was $4.00 per square meter, then calculate the simple payback time. Take the average T for the 120-day heating season to be 15.0 .arrow_forward(a) Calculate the rate of heat transfer by radiation from a car radiator at 110C into a 50.0C environment, if the radiator has an emissivity of 0.750 and a 1.20 m2 surface area. (b) Is this a significant fraction of the heat transfer by an automobile engine? To answer this, assume a horsepower of 200hp (1.5 kW) and the efficiency of automobile engines as 25%.arrow_forward
- A 38% efficient power plant puts out 850 MW of electricalpower. Cooling towers take away the exhaust heat. (a) If theair temperature is allowed to rise 7.0 C°, estimate what volumeof air is heated per day. Will the local climate beheated significantly? (b) If the heated air were to form a layer180 m thick, estimate how large an area it would cover for24 h of operation. Assume the air has density 1.3 kg/m3 andhas specific heat of about 1.0 KJ/kg.Co at constant pressure.arrow_forwardIn an air conditioner, 12.65 MJ of heat transfer occurs from a cold environment in 1.00 h. (a) What mass of ice melting would involve the same heat transfer? (b) How many hours of operation would be equivalent to melting 900 kg ofice? (c) If ice costs 20 cents per kg, do you think the air conditioner could be operated more cheaply than by simply using ice? Describe in detail how you evaluate the relative costs.arrow_forward(a) The data listed in the following table gives hourly measurements of heat flux q (W/m²) at the surface of a solar collector. As an engineer, you estimated the total heat absorbed by a 4 m collector panel during a 13-hr period as h =122.39 W. The panel has an absorption efficiency eab of 45%. If the total heat absorbed is given by h = eab q A dt where A = area and q = heat flux, find K. t 0 1 3 4 5 7 9 11 13 0.10 4.32 5.14 6.05 7.73 K 7.23 5.20 3.38 0.20arrow_forward
- What is the COP of a freezer rated at 200.0 Watts if it takes 30.0 minutes to convert 3.90 kg of water at 25.0 degrees celsius into ice at 0.00 degrees celsius? (Assume all evergy as heat removed from the appliances cold compartment is removed from the water.)arrow_forward(a) What is the best coefficient of performance for a refrigerator that cools an environment at -28.5°C and has heat transfer to another environment at 46.5°C? 3.262 (b) How much work in joules must be done for a heat transfer of 4186 kJ from the cold environment? 1283.26 (c) What is the cost (in cents) of doing this if the work costs 15.0 cents per 3.60 x 106 J (a kilowatt-hour)? 5.35 (d) How many k) of heat transfer occurs into the warm environment? 5469.26 kJ (e) Discuss what type of refrigerator might operate between these temperatures. The inside of the refrigerator (actually freezer) is at (-28.5 °C) so this probably is a commercial meat packing freezer. The exhaust is generally vented to the outside so as to not heat the building too much.arrow_forward(a) Calculate the rate in watts at which heat transfer through radiation occurs (almost entirely in the infrared) to 3.5 m2of the Earth's surface at night. Assume the emissivity is 0.88, the temperature of the Earth is 15°C, and that of outer space is 2.7 K. (Include the sign of the heat transfer to 3.5 m2 of the Earth's surface in the value of your answer.) W (b) Compare the intensity of this radiation with that absorbed by the Earth from the Sun during the day. The intensity of the radiation from the Sun averages about 800 W/m2, only half of which is absorbed by the Earth. Iradiation at night Iabsorbed during day (c)What is the maximum magnetic field strength (in µT) in the outgoing radiation, assuming it is a continuous wave? µTarrow_forward
- (a) How.much heat transfer is required to raise the temperature of a 0.800-kg aluminum pot containing 3.50 kg of water from 25.0°C to the boiling point and then boil away 0.650 kg of water? kcal (b) How long does this take if the rate of heat transfer is 550 W (1 watt = 1 joule/second (1 W = 1 J/s))? Additional Materials O Readingarrow_forwardAfter a hot shower and dishwashing, there seems to be nohot water left in the 65-gal (245-L) water heater. This suggeststhat the tank has emptied and refilled with water at roughly10°C. (a) How much energy does it take to reheat the waterto 45°C? (b) How long would it take if the heater outputis 9500 W?arrow_forwardA copper block is removed from 310ºC oven and immediately dropped into 3.75 L of water at 20ºC.in an insulated cup . The water quickly reaches 25.8ºC and then remains at that temperature. Calculate the following: b) The heat energy supplied to water by the copper block in joules . (Sp.Heat of water = 4186 J/kg°C)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Thermodynamics: Crash Course Physics #23; Author: Crash Course;https://www.youtube.com/watch?v=4i1MUWJoI0U;License: Standard YouTube License, CC-BY