Given the complex numbers A 1 = 6 ∠ 30 and A 2 = 4 + j 5 , (a) convert A 1 to rectangular form: (b) convert A 2 to polar and exponential form: (c) calculate A 3 = ( A 1 + A 2 ) , giving your answer in polar form: (d) calculate A 4 = A 1 A 2 , giving your answer in rectangular form: (e) calculate A 5 = A 1 / ( A 2 * ) giving your answer in exponential form.
Given the complex numbers A 1 = 6 ∠ 30 and A 2 = 4 + j 5 , (a) convert A 1 to rectangular form: (b) convert A 2 to polar and exponential form: (c) calculate A 3 = ( A 1 + A 2 ) , giving your answer in polar form: (d) calculate A 4 = A 1 A 2 , giving your answer in rectangular form: (e) calculate A 5 = A 1 / ( A 2 * ) giving your answer in exponential form.
Solution Summary: The author explains the rectangular form of a complex number A_1 and the exponential and polar forms of complex numbers.
Given the complex numbers
A
1
=
6
∠
30
and
A
2
=
4
+
j
5
, (a) convert
A
1
to rectangular form: (b) convert
A
2
to polar and exponential form: (c) calculate
A
3
=
(
A
1
+
A
2
)
, giving your answer in polar form: (d) calculate
A
4
=
A
1
A
2
, giving your answer in rectangular form: (e) calculate
A
5
=
A
1
/
(
A
2
*
)
giving your answer in exponential form.
Practice Exercise 1.1
Answer the following accordingly:
1. (3-j4) + (10244) then convert to
rectangular form
2. (22000+j13)/(32-17) then convert to
rectangular form
3. Convert 95-j12 to polar form
(a) Determine the value of Z, in the circuit of Figure Q3(a) for maximum power
transfer.
termining the impedance and current of the system, the voltage across the resistor, and the voltage across the inductor.
Could you please forward the response as a print of a handwritten answer?
I got these two answers earlier. Which of them would be correct
Impedance Z= (1000 + j 90.836) ohm
Current I= 0.219∠-5.19° A
Voltage across resistor VR = 219.097∠-5.19° V
Voltage across inductor VL = 165.195∠84.81° V
Impedance will be Z= 1004.052 ∠ 5.12°
Current will be i = 0.221 ∠ -5.19° A.
Volatge across resistor will be VR = 211.9∠ -5.19° V
Volatge across inductor will be VL = 165.12 ∠ 84.81°V
Chapter 2 Solutions
Power System Analysis and Design (MindTap Course List)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.