Concept explainers
Point charges of equal magnitude but of opposite sign are positioned the charge +q at z = -d/2 and charge -q at z= -d/2 The charges in this configuration form an e1ectric dispole (a) Find the electric field intensity E everywhere on the z-axis is (b) Evaluate pan a result at the origin
(c) Find the electric geld intensity everywhere on the zy plane, expressing your result as a function of radius p in cylindrical coordinates, (d) Evaluate your pan c result at the origin (e) Simplify your part c result for the case in which p >> d.
(a)
The electric field intensity on z -axis.
Answer to Problem 2.7P
The required electric field intensity is:
Explanation of Solution
Given Information:
The point charge
Calculation:
Let
Conclusion:
The required electric field intensity is:
(b)
The electric field intensity at origin.
Answer to Problem 2.7P
The required electric field intensity is,
Explanation of Solution
Given Information:
The point charge
Calculation:
The electric field at origin,
Conclusion:
The required electric field intensity is
(c)
The electric field intensity on x-y plane as a function of radius in cylindrical coordinates.
Answer to Problem 2.7P
The required electric field intensity is
Explanation of Solution
Given Information:
The point charge
Calculation:
Let
Conclusion:
The required electric field intensity is
(d)
The electric field intensity at origin.
Answer to Problem 2.7P
The required electric field intensity is
Explanation of Solution
Given Information:
The point charge
Calculation:
The electric field intensity at origin,
Conclusion:
The required electric field intensity is
(e)
The electric field intensity on x-y plane when
Answer to Problem 2.7P
The required electric field intensity is,
Explanation of Solution
Given Information:
The point charge
Calculation:
When
Conclusion:
The required electric field intensity is
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Chapter 2 Solutions
Engineering Electromagnetics
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