Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 2, Problem 70E
Interpretation Introduction
Interpretation:
The energy in kilocalories, if a gas stove releases
Concept introduction:
Energy is a physical quantity. It is the capacity to do work. The energy can be transferred from one form to another form. The energy can be expressed in joules, kilojoules and calories.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A student burns a small snack food item and finds that it releases 40,800 J of energy. How many Calories does this food item contain? Round your answer to the nearest 0.01
Expressing amounts of energy in different energy units is necessary to solve many chemistry problems. For practice, complete the following table.
The Joule (J) is the SI unit of energy.
The calorie (cal) is the amount of energy needed to raise the temperature of 1 g of water by 1°C, 1 cal = 4.184)
The British Thermal Unit (BTU) is the amount of energy needed to raise the temperature of 1 pound of water by 1°F. 1 BTU - 1055J
BTU
7.67
kJ
0.463
kcal
0.181
Sodium (Na) metal undergoes a chemical reaction with chlorine (Cl) gas to yield sodium chloride, or common table salt. If 1.00 g of sodium reacts with 1.54 g of chlorine, 2.54 g of sodium chloride is formed and 17.9 kJ of heat is released. How much sodium and how much chlorine in grams would have to react to release 171 kcal of heat?
Chapter 2 Solutions
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Ch. 2 - Prob. 2.1CECh. 2 - Prob. 2.2CECh. 2 - Prob. 2.3CECh. 2 - Prob. 2.4CECh. 2 - Prob. 2.5CECh. 2 - Prob. 2.6CECh. 2 - Prob. 2.7CECh. 2 - Prob. 2.8CECh. 2 - Prob. 2.9CECh. 2 - Prob. 2.10CE
Ch. 2 - Prob. 2.11CECh. 2 - Prob. 2.12CECh. 2 - Prob. 2.13CECh. 2 - Prob. 2.14CECh. 2 - Prob. 2.15CECh. 2 - Prob. 2.16CECh. 2 - Prob. 2.17CECh. 2 - Prob. 2.18CECh. 2 - Prob. 1KTCh. 2 - Prob. 2KTCh. 2 - Prob. 3KTCh. 2 - Prob. 4KTCh. 2 - Prob. 5KTCh. 2 - Prob. 6KTCh. 2 - Prob. 7KTCh. 2 - Prob. 8KTCh. 2 - Prob. 9KTCh. 2 - Prob. 10KTCh. 2 - Prob. 11KTCh. 2 - Prob. 12KTCh. 2 - Prob. 13KTCh. 2 - Prob. 14KTCh. 2 - Prob. 15KTCh. 2 - Prob. 16KTCh. 2 - Prob. 17KTCh. 2 - Prob. 18KTCh. 2 - Prob. 19KTCh. 2 - Prob. 20KTCh. 2 - Prob. 21KTCh. 2 - Prob. 22KTCh. 2 - Prob. 23KTCh. 2 - Prob. 24KTCh. 2 - Prob. 25KTCh. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10ECh. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 28ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50ECh. 2 - Prob. 51ECh. 2 - Prob. 52ECh. 2 - Prob. 53ECh. 2 - Prob. 54ECh. 2 - Prob. 55ECh. 2 - Prob. 56ECh. 2 - Prob. 57ECh. 2 - Prob. 58ECh. 2 - Prob. 59ECh. 2 - Prob. 60ECh. 2 - Prob. 61ECh. 2 - Prob. 62ECh. 2 - Prob. 63ECh. 2 - Prob. 64ECh. 2 - Prob. 65ECh. 2 - Prob. 66ECh. 2 - Prob. 67ECh. 2 - Prob. 68ECh. 2 - Prob. 69ECh. 2 - Prob. 70ECh. 2 - Prob. 71ECh. 2 - Prob. 72ECh. 2 - Prob. 73ECh. 2 - Prob. 74ECh. 2 - Prob. 75ECh. 2 - Prob. 76ECh. 2 - Prob. 77ECh. 2 - Prob. 78ECh. 2 - Prob. 79ECh. 2 - Prob. 80ECh. 2 - Prob. 81ECh. 2 - Prob. 82ECh. 2 - Prob. 83ECh. 2 - Prob. 84ECh. 2 - Prob. 85ECh. 2 - Prob. 86ECh. 2 - Prob. 87ECh. 2 - Prob. 88ECh. 2 - Prob. 89ECh. 2 - Prob. 90ECh. 2 - Prob. 91ECh. 2 - Prob. 92ECh. 2 - Prob. 93ECh. 2 - Prob. 94ECh. 2 - Prob. 95ECh. 2 - Prob. 96ECh. 2 - Prob. 1STCh. 2 - Prob. 2STCh. 2 - Prob. 3STCh. 2 - Prob. 4STCh. 2 - Prob. 5STCh. 2 - Prob. 6STCh. 2 - Prob. 7STCh. 2 - Prob. 8STCh. 2 - Prob. 9STCh. 2 - Prob. 10STCh. 2 - Prob. 11STCh. 2 - Prob. 12STCh. 2 - Prob. 13STCh. 2 - Prob. 14ST
Knowledge Booster
Similar questions
- 1-86 The specific heats of some elements at 25oC are as follows: aluminum = 0.215 cal/g · oC; carbon (graphite) = 0.170 caI/g oC; iron = 0.107 cal/g mercury = 0.033 1 caI/g oC. (a) Which element would require the smallest amount of heat to raise the temperature of 100 g of the element by 10oC? (b) If the same amount of heat needed to raise the temperature of 1 g of aluminum by 25oC were applied to 1 g of mercury, by how many degrees would its temperature be raised? (c) If a certain amount of heat is used to raise the temperature of 1.6 g of iron by 10oC, the temperature of 1 g of which element would also be raised by 10oC, using the same amount of heat?arrow_forward1-93 The specific heat of urea is 1.339 J/g . If one adds 60.0 J of heat to 10.0 g of urea at 20oC, what would be the final temperature?arrow_forward1-91 In calculating the specific heat of a substance, the following data are used: mass = 92.15 g; heat = 3.200 kcal; rise in temperature = 45oC. How many significant figures should you report in calculating the specific heat?arrow_forward
- 1-67 If 168 g of an unknown liquid requires 2750 cal of heat to raise its temperature from 26oC to 74oC, what is the specific heat of the liquid?arrow_forward1-87 Water that contains deuterium rather than ordinary hydrogen (see Section 2-4D) is called heavy water. The specific heat of heavy water at 25oC is 4.2 17 J/g oC. Which requires more energy to raise the temperature of 10.0 g by 10oC, water or heavy water?arrow_forwardExpressing amounts of energy in different energy units is necessary to solve many chemistry problems. For practice, complete the following table. The Joule (J) is the SI unit of energy. 1 calorie (cal) = 4.184 J J cal kJ 566 156 0.719arrow_forward
- A peanut butter sandwich provides about 1.1 ✕ 103 kJ of energy. A typical adult uses about 95 kcal/hr of energy while sitting. If all of the energy in one peanut butter sandwich were to be burned off by sitting, how many hours would it be before this energy was used? (A kcal is a dietary calorie. There are 4.184 J/cal.) Only typed solutionarrow_forwardExpressing amounts of energy in different energy units is necessary to solve many chemistry problems. For practice, complete the following table. The Joule (J) is the SI unit of energy. 1 calorie (cal) 4.184) 1 kWh = 3.600 x 105 3 245 kWh 200 kcal 338arrow_forwardWhich of the following objects has the greatest kinetic energy?a 1,000-kg carmoving at 50 km/harrow_forward
- A thermometer is taken from a room where the temperature is 18°C to the outdoors, where the temperature is -12°C. After one minute the thermometer reads 9°C. (a) What will the reading on the thermometer be after 3 more minutes? -1.7 (b) When will the thermometer read -11°C? minutes after it was taken to the outdoors.arrow_forwardA tablespoon of olive oil contains 115 nutritional calories. How many joules of energy are in this tablespoon?arrow_forwardIf a person practicing yoga for one hour burns 285 kilocalories (kcal), how many joules (J) of energy have they burned?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning