General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 20, Problem 31E
(a)
To determine
The magnetic force on a charge
(b)
To determine
The work done on the charge.
(c)
To determine
The comparison of the EMF found using the equation
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A capacitor in a telephone circuit has a capacitance of 3μF. What current flows through it when 15V at 800Hz is impressed across it? answer should be in polar form
A electric heater that draws 13.5 A of dc current has been left on for 10 min. How many electrons that have passed through the heater during that time? (e = 1.60 × 10-19 C). Please answer fast i'll rate up:)
Find the direction of the current in the resistor shown in
Figure P20.16 (a) at the instant the switch is closed, (b) after
the switch has been closed for several minutes, and (c) at the
instant the switch is opened.
F000
DOC
S
E
Figure P20.16
www
R
Chapter 20 Solutions
General Physics, 2nd Edition
Ch. 20 - Prob. 1RQCh. 20 - Prob. 2RQCh. 20 - Prob. 3RQCh. 20 - Prob. 4RQCh. 20 - Prob. 5RQCh. 20 - Prob. 6RQCh. 20 - Prob. 7RQCh. 20 - Prob. 8RQCh. 20 - Prob. 9RQCh. 20 - Prob. 10RQ
Ch. 20 - Prob. 11RQCh. 20 - Prob. 12RQCh. 20 - Prob. 13RQCh. 20 - Prob. 1ECh. 20 - Prob. 2ECh. 20 - Prob. 3ECh. 20 - Prob. 4ECh. 20 - Prob. 5ECh. 20 - Prob. 6ECh. 20 - Prob. 7ECh. 20 - Prob. 8ECh. 20 - Prob. 9ECh. 20 - Prob. 10ECh. 20 - Prob. 11ECh. 20 - Prob. 12ECh. 20 - Prob. 13ECh. 20 - Prob. 14ECh. 20 - Prob. 15ECh. 20 - Prob. 16ECh. 20 - Prob. 17ECh. 20 - Prob. 18ECh. 20 - Prob. 19ECh. 20 - Prob. 20ECh. 20 - Prob. 21ECh. 20 - Prob. 22ECh. 20 - Prob. 23ECh. 20 - Prob. 24ECh. 20 - Prob. 25ECh. 20 - Prob. 26ECh. 20 - Prob. 27ECh. 20 - Prob. 28ECh. 20 - Prob. 29ECh. 20 - Prob. 30ECh. 20 - Prob. 31ECh. 20 - Prob. 32ECh. 20 - Prob. 33ECh. 20 - Prob. 34ECh. 20 - Prob. 35ECh. 20 - Prob. 36ECh. 20 - Prob. 37ECh. 20 - Prob. 38ECh. 20 - Prob. 39ECh. 20 - Prob. 40ECh. 20 - Prob. 41ECh. 20 - Prob. 42ECh. 20 - Prob. 43ECh. 20 - Prob. 44ECh. 20 - Prob. 45ECh. 20 - Prob. 46ECh. 20 - Prob. 47ECh. 20 - Prob. 48ECh. 20 - Prob. 49ECh. 20 - Prob. 50ECh. 20 - Prob. 51ECh. 20 - Prob. 52ECh. 20 - Prob. 53ECh. 20 - Prob. 54ECh. 20 - Prob. 55ECh. 20 - Prob. 56ECh. 20 - Prob. 57ECh. 20 - Prob. 58ECh. 20 - Prob. 59ECh. 20 - Prob. 60ECh. 20 - Prob. 61ECh. 20 - Prob. 62ECh. 20 - Prob. 63ECh. 20 - Prob. 64ECh. 20 - Prob. 65ECh. 20 - Prob. 66ECh. 20 - Prob. 67ECh. 20 - Prob. 68ECh. 20 - Prob. 69ECh. 20 - Prob. 70ECh. 20 - Prob. 71ECh. 20 - Prob. 72ECh. 20 - Prob. 73ECh. 20 - Prob. 74ECh. 20 - Prob. 75ECh. 20 - Prob. 76ECh. 20 - Prob. 77ECh. 20 - Prob. 78ECh. 20 - Prob. 79ECh. 20 - Prob. 80ECh. 20 - Prob. 81ECh. 20 - Prob. 82ECh. 20 - Prob. 83ECh. 20 - Prob. 84ECh. 20 - Prob. 85ECh. 20 - Prob. 86ECh. 20 - Prob. 87ECh. 20 - Prob. 88ECh. 20 - Prob. 89ECh. 20 - Prob. 90ECh. 20 - Prob. 91ECh. 20 - Prob. 92ECh. 20 - Prob. 93ECh. 20 - Prob. 94ECh. 20 - Prob. 95E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- . The generator at a large power plant has an output of 1,000,000 kW at 24,000 V. (a) If it were a DC generator, what would he the current in it? (b) What is its energy output each day—in joules and in kilowatt—hours? (c) If this energy is sold at a price of 10 cents per kilowatt-hour, how much revenue does the power plant generate each day?arrow_forwardFigure P18.37 shows a simplified model of a cardiac defibrillator, a device used to patients in ventricular fibrillation. When the switch S is toggled to the left, the capacitor C charges through the resistor R .When the switch is toggled to the right, the capacitor discharges current through the patients torso, modeled as the resistor Rtorso, allowing the hearts normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 8.00 F and = 1250 V, find the value of R required to charge the capacitor to a voltage of 775 V in 1.50 s. (b) If the capacitor is then discharged across the patients torso with, Rtorso = 1250 , calculate the voltage across the capacitor after 5.00 ms. Figure P18.37arrow_forwardIntegrated Concepts (a) What energy is dissipated by a lightning bolt having a 20,000-A current, a voltage of 1.00102 MV, and a length of 1.00 ms? (b) What mass of tree sap could be raised from 18.0°C to its boiling point and then evaporated by this energy, assuming sap has the same thermal characteristics as water?arrow_forward
- Figure P18.37 shows a simplified model of a cardiac defibrillator, a device used to patients in ventricular fibrillation. When the switch S is toggled to the left, the capacitor C charges through the resistor R .When the switch is toggled to the right, the capacitor discharges current through the patients torso, modeled as the resistor Rtorso, allowing the hearts normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 8.00 F and = 1250 V, find the value of R required to charge the capacitor to a voltage of 775 V in 1.50 s. (b) If the capacitor is then discharged across the patients torso with, Rtorso = 1250 , calculate the voltage across the capacitor after 5.00 ms. Figure P18.37arrow_forwardThe figure below shows a simplified model of a cardiac defibrillator, a device used to resuscitate patients in ventricular fibrillation. When the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 7.00 µF and e m f = 1270 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 795 V in 1.60 s. Ω (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1230 Ω, calculate the voltage (in V) across the capacitor after 5.50 ms. Varrow_forwardA rail gun uses electromagnetic forces to accelerate a projectile to very high velocities. The basic mechanism of acceleration is relatively simple and can be illustrated in the following example. A metal rod of mass 40.0 g and electrical resistance 0.300 Ω rests on parallel horizontal rails that have negligible electric resistance. The rails are a distance L = 9.00 cm apart. (Figure 1)The rails are also connected to a voltage source providing a voltage of V = 5.00 V .The rod is placed in a vertical magnetic field. The rod begins to slide when the field reaches the value B = 0.131 T . Assume that the rod has a slightly flattened bottom so that it slides instead of rolling. Use 9.80 m/s^2 for the magnitude of the acceleration due to gravity. A) Find μ_s, the coefficient of static friction between the rod and the rails. Give the answer numericallyarrow_forward
- A 0.718 kg0.718 kg toy car is powered by four AA batteries (6.00 V total) connected directly to a small DC motor. The car has an effective energy conversion efficiency of 36.1%,36.1%, meaning that 36.1%36.1% of the electric energy applied to the motor is converted into translational kinetic energy. After 7.88 s7.88 s, the car, which is initially at rest, reaches a speed of 3.43 m/s.3.43 m/s. What is the average current supplied to the car's motor?arrow_forwardAn ordinary gold wedding ring is tossed end over end into a running MRI machine with a 4.0 T field. The ring spends 1.2 s in the field, during which it completes 60 full rotations. If the ring has a resistance of 6.02 and a diameter of 19 mm, what is the average power Pavg dissipated by the ring? Pave TOOLS ΣΤΟΥ Warrow_forwardThe figure below shows a simplified model of a cardiac defibrillator, a device used to resuscitate patients in ventricular fibrillation. S R Rorso + The capacitor C charge through the resistor R (when the switch S is toggled to left) and discharge current through the patient's torso which is of resistance (when the switch S is toggled to right). This phenomenon allows the heart's normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 7.0 µF; ɛ = 1240 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 800 V in 2.1 s. (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1200 Q, calculate the voltage (in V) across the capacitor after 4.0 ms.arrow_forward
- The severity of an electrical shock depends on all of the following except: O The duration of the contact with the source of the shock. O Whether the shock is AC (alternating current) or DC (direct current). Whether the source of the electricity is a battery or a DC power supply. O The path the current takes through the body.arrow_forwardThe figure below shows a simplified model of a cardiac defibrillator, a device used to resuscitate patients in ventricular fibrillation. R HINT E S C When the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. R torso V (a) If the capacitor is initially uncharged with C = 7.25 µF and E = 1220 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 755 V in 1.60 s. Ω (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1270 , calculate the voltage (in V) across the capacitor after 4.50 ms.arrow_forwardA battery of a computer has an emf of 12 Volts. The computer uses l=360mA while running. If the computer runs out of battery in t=7.3 hours, what is the energy stored in the battery?(answer will be answered in units of Wh....note: in order to transform Joule into Wh, which means Watt hours, just divide the number obtained in Joule by 3600-s)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
What is Electromagnetic Induction? | Faraday's Laws and Lenz Law | iKen | iKen Edu | iKen App; Author: Iken Edu;https://www.youtube.com/watch?v=3HyORmBip-w;License: Standard YouTube License, CC-BY