Web Development and Design Foundations with HTML5 (9th Edition) (What's New in Computer Science)
9th Edition
ISBN: 9780134801148
Author: Terry Felke-Morris
Publisher: PEARSON
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Chapter 2.14, Problem 2CP
Program Plan Intro
Ordered List:
Ordered list in html is the data which is in sequential manner. It is used to keep the related items together in a sequential and specified way.
Unordered List:
Unordered list in html is the data which is not in sequential manner. In this lists, the group of related items are not in specified way.
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Chapter 2 Solutions
Web Development and Design Foundations with HTML5 (9th Edition) (What's New in Computer Science)
Ch. 2.6 - Prob. 1CPCh. 2.6 - Prob. 2CPCh. 2.6 - Prob. 3CPCh. 2.14 - Prob. 1CPCh. 2.14 - Prob. 2CPCh. 2.14 - Prob. 3CPCh. 2.17 - Prob. 1CPCh. 2.17 - Prob. 2CPCh. 2.17 - Prob. 3CPCh. 2 - Prob. 3MC
Ch. 2 - Prob. 2MCCh. 2 - Prob. 1MCCh. 2 - Prob. 4MCCh. 2 - Prob. 5MCCh. 2 - Prob. 6MCCh. 2 - Prob. 7MCCh. 2 - Prob. 8MCCh. 2 - Prob. 9MCCh. 2 - Prob. 10MCCh. 2 - Prob. 11FIBCh. 2 - ___________ can be used to display characters such...Ch. 2 - Prob. 13FIBCh. 2 - Prob. 14FIBCh. 2 - Prob. 15FIBCh. 2 - Prob. 16SACh. 2 - Prob. 1AYKCh. 2 - Prob. 2AYKCh. 2 - Prob. 3AYKCh. 2 - Prob. 1HOECh. 2 - Prob. 2HOECh. 2 - Prob. 3HOECh. 2 - Prob. 4HOECh. 2 - Prob. 5HOECh. 2 - Prob. 6HOECh. 2 - Prob. 7HOECh. 2 - Prob. 8HOECh. 2 - Prob. 9HOECh. 2 - Prob. 10HOECh. 2 - Prob. 1FWD
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- Lists can be represented as Linked List or Array based List True Falsearrow_forwardASSUMING C LANGUAGE True or False: You can have the data portion of a Linked List be a Struct containing a Linked List itselfarrow_forwardfind_last(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the last element of the list which is equal to the second input; if it cannot be found, returns None instead. >>> find_last(['a', 'b', 'b', 'a'], 'b') 2 >>> ind = find_last(['a', 'b', 'b', 'a'], 'c') >>> print(ind) None • find_first(my_list, x): Takes two inputs: the first being a list and the second being any type. Returns the index of the first element of the list which is equal to the second input; if it cannot be found, returns None instead. >>> find_first(['a', 'b', 'b', 'a'], 'b') 1 >>> ind = find_first(['a', 'b', 'b', 'a'], 'c') >>> print(ind) None In pythonarrow_forward
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