Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Question
Chapter 28, Problem 61P
(a)
To determine
The rate at which battery supplies energy
(b)
To determine
The rate of joule heating in the resistor
(c)
To determine
The rate at which energy is stored in the inductor.
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a S₁
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Chapter 28 Solutions
Physics for Scientists and Engineers
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- When the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. (a)If the capacitor is initially uncharged with C = 8.25 µF and = 1270 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 755 V in 1.70 s. answer in Ω b) If the capacitor is then discharged across the patient's torso with Rtorso = 1260 Ω, calculate the voltage (in V) across the capacitor after 4.50 ms. answer in Varrow_forwardConsider the circuit shown below, with an initially uncharged capacitor C and two identical resistors R. R IR ww V T Ic с C R At the instant the switch is closed, the current through the capacitor will be: V/R, directed Down ✓ At the instant the switch is closed, the current through the right-side resistor will be: V/R, directed Down ✓ After the switch has been closed for a very long time, it is opened. The current through the right-side resistor will be V/R, directed Down The switch is closed at t = 0. At t = ∞ (long after) the current through the right-side resistor will be: zero The switch is closed at t = 0. At t = ∞ (long after) the current through the capacitor will be: V/R, directed Down V After the switch has been closed for a very long time, it is opened. The current through the capacitor will be? V/R, directed Uparrow_forward95 In Fig. 27-79, E, = 6.00 V, = 12.0 V, R = 100 0, R, = 200 N, and R, = 300 N. One point of the circuit is grounded (V = the (a) size and (b) direction (up or down) of the current through resistance 1, the (c) size and (d) direction (left or right) of the current through resistance 2, and the (e) size and (f) direction of the current through resistance 3? (g) What is the electric potential at point A? 0), What arearrow_forward
- Suppose the following circuit is left open for a long time. 24 V 5000 Ω 80mF (a) What is the energy stored in the capacitor 90s after we close the switch? (b) What is the energy dissipated by the resistor during the first 90s since the switch is closed?arrow_forwardWhen the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rtorso, allowing the heart's normal rhythm to be reestablished. (a) If the capacitor is initially uncharged with C = 7.00 µF and = 1270 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 795 V in 1.70 s. Ω (b) If the capacitor is then discharged across the patient's torso with Rtorso = 1270 Ω, calculate the voltage (in V) across the capacitor after 4.50 ms.arrow_forward**57 Go In Fig. 30-63, R = 15 N, L = 5.0 H, the ideal battery has & = 10 V, and the fuse in the upper branch is an ideal 3.0 A fuse. It has Fuse R zero resistance as long as the cur- rent through it remains less than 3.0 L. A. If the current reaches 3.0 A, the fuse “blows" and thereafter has in- finite resistance. Switch S is closed Fig. 30-63 Problem 57. at time t= 0. (a) When does the fuse blow? (Hint: Equation 30-41 does not apply. Rethink Eq. 30-39.) (b) Sketch a graph of the current i through the inductor as a function of time. Mark the time at which the fuse blows.arrow_forward
- An initially uncharged capacitor is connected as shown. If the switch is closed at t0, the time it takes the capacitor to reach BO% of its final voltage is T. f the time constant of the circuit is t, determine T/r. R ww O16 22 5.0 3.0 1.9arrow_forwardIn the circuit ɛ =4.6 kV, C = 7.9µF, R, = R2 = R3 = 0.74 MQ. With C completely uncharged, switch S is suddenly closed at t=0, a) at t=0 find the current in all resistors b) Fint the current in all resistors at t=, c) potential difference across resesitor 2 at t=0 and t=∞ R Rg Ro ww-arrow_forwardConsider a circuit with three resistors, R1 = 225 Ω, R2 = 155 Ω, and R3 = 135 Ω, connected in parallel with a 24.0-Vbattery. (These are the same resistances and battery as in the series circuit in Example 21-10.) Find (a) the total currentsupplied by the battery and (b) the current through each resistor.arrow_forward
- A capacitor of capacitance C = 1 μF has been charged so that the potential difference between its plates is V0 = 295 V. The capacitor is then connected to a resistor of resistance R = 11.5 kΩ. The switch S is closed, and the capacitor begins to discharge. Calculate the time T in s after which the charge on the capacitor has decreased to one fourth its maximum value.arrow_forwardFor the circuit shown below, ε=22 V, L=7.5 mH, and R=6Ω. After steady state is reached with S1 closed and S2 open, at t=0, S2 is closed and S1 is opened. Determine (a) the current through L at t=0, (b) the current through L at t=4.5×10-4 s, (c) the voltage across R on the right at t=4.5×10-4 s, and (d) the rate at which current through L changes at t=4.5×10−4 s. The current through L at t=0 is__________A. The current through L at t=4.5×10-4 s is_____A. The voltage across R at t=4.5×10-4 s is______V. The rate at which current through L changes at t=4.5×10-4 s is______A/s.arrow_forward() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. R ww C In the circuit shown in the figure, the S switch is closed at t = 0 and the capacitors, which are completely empty, begin to fill. Here E = 50 V, C = 4 µF and R = 15 N. R ww A) What is the time constant of the circuit, T, in units of microseconds? Yanıt: B) When t = T, what is the total charge, in units of microcoulomb, accumulated in the capacitors?arrow_forward
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