College Physics (10th Edition)
10th Edition
ISBN: 9780321902788
Author: Hugh D. Young, Philip W. Adams, Raymond Joseph Chastain
Publisher: PEARSON
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Chapter 29, Problem 7CQ
To determine
What is the energy required to remove a
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A visible (violet) emission spectral line for chromium (Cr) occurs at wavelength λ = 425.435 nm.
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A visible (violet) emission spectral line for chromium (Cr) occurs at wavelength λ = 425.435 nm.What is the frequency (ν) of this light?(Mind the units carefully. Give your answers to six significant figures.)What is the magnitude of the energy change associated with the emission of one mole of photons of light with this wavelength?
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Chapter 29 Solutions
College Physics (10th Edition)
Ch. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - Prob. 8CQCh. 29 - Prob. 9CQCh. 29 - Prob. 10CQ
Ch. 29 - Prob. 1MCPCh. 29 - Prob. 2MCPCh. 29 - Prob. 3MCPCh. 29 - Prob. 4MCPCh. 29 - Prob. 5MCPCh. 29 - Prob. 6MCPCh. 29 - Prob. 7MCPCh. 29 - Prob. 8MCPCh. 29 - Prob. 9MCPCh. 29 - Prob. 10MCPCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Prob. 5PCh. 29 - What is the ratio of the number of different 3d...Ch. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - For bromine (Z = 35), make a list of the number of...Ch. 29 - (a) Write out the electron configuration (1s2 2s2,...Ch. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - Prob. 27GPCh. 29 - Prob. 28GPCh. 29 - An electron has spin angular momentum and orbital...Ch. 29 - Prob. 30GPCh. 29 - Prob. 31GPCh. 29 - Prob. 32GPCh. 29 - Prob. 33GPCh. 29 - Prob. 34GPCh. 29 - Prob. 35GPCh. 29 - Prob. 36GPCh. 29 - Prob. 37GPCh. 29 - Prob. 38GPCh. 29 - Prob. 39PPCh. 29 - Prob. 40PPCh. 29 - Prob. 41PPCh. 29 - Prob. 42PP
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- A hydrogen atom has its electron in the n-3 state. How much energy would have to be absorbed by the atom for it to become ionized from this level? What is the frequency of the photon that could produce this result? An atom has 46 electrons. What is the smallest value of n needed so that all 46 electrons occupy the lowest possible quantum states consistent with the Pauli exclusion principle? O 1.51 eV 3.65 x 10^14 Hz, n = 5 O 1.51 eV 3.93 x 10^14 Hz. n=5 O 1.58 eV 3.93 x 10^14 Hz, n=5 1.51 eV 3.65 x 10^14 Hz. n-4 O 144 eV 3.65 x 10^14 Hz, n=6arrow_forwardA hydrogen atom emits a photon when its electron shifts from a higher energy level to a lower one. Suppose that one atom emits a photon whose wavelength equals 656 nm. If the energy levels are defined by the quantum number n (where n = 1, 2, 3, ), what were the initial and final values of n? ni=. ? nf=. ?arrow_forward4. a. An electron in a hydrogen atom falls from an initial energy level of n-5 to a final level of n - 2. Find the energy, frequency, and wavelength of the photon that will be [For hydrogen: E-13.6 eV/n²] emitted for this sequence. b. A photon of energy 2.794 eV is absorbed by a hydrogen atom, causing its electron to be released with a kinetic energy of 2.250 eV. In what energy level was the electron? c. Find the wavelength of the matter wave associated with a proton moving at a speed of 350 m/s.arrow_forward
- What is the average radius of the orbit of an electron in the n=2 energy level of an oxygen atom (Z=8)? Express your answer in pico-meters.arrow_forwardThe light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying EH=−RH/n2EH=−RH/n2 where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state. Be careful about units. The Rydberg constant in eV is 13.605693009 eV That would be multiplied by the charge on the electron 1.602× 10-19 C to give 2.18× 10-18 J A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules. The following questions are intended to help you understand the connection between…arrow_forwarda) An electron in a hydrogen atom has energy E= -3.40 eV, where the zero of energy is at the ionization threshold. In the Bohr model, what is the angular momentum of the electron? Express your result as a multiple of ħ. Ans. b) What is the deBroglie wavelength of the electron when it is in this state? Ans. c) When the electron is in this state, what is the ratio of the circumference of the orbit of the electron to the deBroglie wavelength of the electron? Ans. d) The electron makes a transition from the state with energy E= -3.40 eV to the ground state, that has energy -13.6 eV. What is the wavelength of the photon emitted during this transition? Ans.arrow_forward
- For a hydrogen-like atom (the atom contains only one electron, like singly ionized He, doubly ionized Lithium, etc.), the energy levels are given by En = -Z2(13.6)/n2 eV where Z is the atomic number. If an electron in a doubly ionized Lithium atom jumps from the 2nd excited state to the ground state, what would be the wavelength of the emitted photon? A) 3.21 nm B) 3.21 pm C) 6.42 pm D) none of these.arrow_forwardA hydrogen atom is in state N= 3, where N = 1 is the lowest energy state. What is K+U in electron volts for this atomic hydrogen energy state? E3 = eV The hydrogen atom makes a transition to state N = 2. What is K+U in electron volts for this lower atomic hydrogen energy state? E₂ = eV What is the energy in electron volts of the photon emitted in the transition from level N = 3 to N = 2? Ephoton = eVarrow_forwardA 2.55 eV photon is emitted from a hydrogen atom. What are the Balmer formula n and m values corresponding to this emission?arrow_forward
- The energy levels of the Bohr model for the atom can be expressed mathematically as En -13.6 eV, where Z is the atomic number, and n is the quantum number. This model is reasonably accurate for hydrogen and for singly ionized helium. The photon associated with the transition of an electron from the ground state to the first excited state in singly ionized helium has a different wavelength than that associated with a similar transition in hydrogen. Which of the following correctly describes the wavelengths of these two photons in terms of the energy level diagrams for hydrogen and helium? The photon absorbed by hydrogen has a longer wavelength than that absorbed by helium, because the energy levels in the diagram for hydrogen are more closely spaced than in the diagram for helium. B The photon absorbed by hydrogen has a shorter wavelength than that absorbed by helium, because the energy levels in the diagram for hydrogen are more closely spaced than in the diagram for helium. The photon…arrow_forwarda. The electron of a hydrogen atom is excited into a higher energy level from a lower energy level. A short time later the electron relaxes down to the no = 1 energy level, releasing a photon with a wavelength of 93.83 nm. Compute the quantum number of the energy level the electron relaxes from, nhi. Note: the Rydberg constant in units of wavenumbers is 109,625 cm-1 nhi =16 b. What would the wavenumber, wavelength and energy of the photon be if instead no = 1 and nhi = 4? V: 6.9121e14 x (cm-¹) λ: (nm) E: 45.8e-20 ✓ (1)arrow_forwardA hydrogen atom is in the ground state. It absorbs energy and makes نقطة واحدة a transition to the n = 3 excited state. The atom returns to the ground state by emitting two photons. What are their ?wavelengths None of these O 5.66x10^-7 m and 2.12x10^-7 m O 6.65×10^-7 m and 2.21×10^-7 m 6.56×10^-7 m and 1.22×10^-7 m Oarrow_forward
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