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(Geometry: area of a regular polygon) A regular polygon is an n-sided polygon in which all sides are of the same length and all angles have the same degree (i.e., the polygon is both equilateral and equiangular). The formula for computing the area of a regular polygon is
Here, s is the length of a side. Write a
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Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
- (Random Walk Robot) A robot is initially located at position (0, 0) in a grid [−5, 5] × [−5, 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move in and the current position of the robot. Use formatted output to print the direction (Down, Up, Left or Right) in the left. The direction takes 10 characters in total and fill in the field with empty spaces. The statement to print results in such format is given below: cout << setw(10) << left << ‘Down’ << ... ; cout << setw(10) << left << ‘Up’ << ...; If the robot moves back to the original place (0,0), print “Back to the origin!” to the console and stop the program. If it reaches the boundary of the grid, print “Hit the boundary!” to the console and stop the program. A successful run of your code may look like: Due to randomness, your results may have a different…arrow_forward(Geometry: great circle distance) The great circle distance is the distance between two points on the surface of a sphere. Let (x1, y1) and (x2, y2) be the geographi- cal latitude and longitude of two points. The great circle distance between the two points can be computed using the following formula: d = radius * arccos(sin(x1) * sin(x2) + cos(x1) * cos(x2) * cos(y1 - y2)) Write a program that prompts the user to enter the latitude and longitude of two points on the earth in degrees and displays its great circle distance. The average earth radius is 6,378.1 km. The latitude and longitude degrees in the formula are for north and west. Use negative to indicate south and east degrees.arrow_forwardFind the error in the following codearrow_forward
- (Algebra: solve 2 x 2 linear equations) You can use Cramer's rule to solve the following 2 x 2 system of linear equation: ax + by = e ed – bf af- ec ad - bc cx + dy = f ad – bc y = Write a program that prompts the user to enter a and f and display the result. If ad - bc is 0 b, c, d , e, , report that The equation has no solution.arrow_forward(Prove using Direct Proof)Theorem: Directly prove that if n is an odd integer then n^2 is also an odd integer.Proof:arrow_forward(Area of a convex polygon) A polygon is convex if it contains any line segment that connects two points of the polygon. Write a program that prompts the user to enter the number of points in a convex polygon, then enter the points clockwise, and display the area of the polygon. Sample Run Enter the number of points: 7 Enter the coordinates of the points: -12 0 -8.5 10 0 11.4 5.5 7.8 6 -5.5 0 -7 -3.5 -5.5 The total area is 244.575arrow_forward
- "NEED ONLY CODE NO EXPLANATION" Harry has a big wall clock, that got hit while he was playing. Now, the minute hand doesn't rotate by the angle 2π/3600 each second, but now it moves according to different angle x. You can assume that coordinates of the centre of the clock are (0, 0) and the length of the minute hand is l. One endpoint of the minute hand is always located at the clock centre; the other endpoint is initially located at the point (0, l). One second later, Harry observes that this endpoint is at distance d above the x-axis, i.e., the y-coordinate of this endpoint is equal to d. Harry is curious about where the minute hand will be (specifically, its y-coordinate) after t seconds. Because t can be very large, Harry can't wait for that moment. Please help him to write a python code that prints a single line containing the output. Input: 4 2 2 Output 4arrow_forward(True/False): A segment descriptor does not contain segment size informationarrow_forwardx4 + 2x3 – 7x2 + 3 = 0 a) One of the root of the equation lies in the range (1.0, 2.0). Find this root in 100 iterations using the bisection method. b) Draw the graph of the function between points (0, 2). Your code should include the following steps: • Write the steps of the bisection function (if, else...) and explain each step. (Explain each step in English or Turkish.) • Your code should calculate the root. • Graphic; Variables of x and y axes should be written, x and y axis names should be written, Series should be written to calculate x axis. Use the linspace() for the x series of the graph and section the range 0-2 into 100 pięces.arrow_forward
- (Financial: credit card number validation) Credit card numbers follow certain pat- terns. A credit card number must have between 13 and 16 digits. It must start with: 4 for Visa cards 5 for Master cards 37 for American Express cards 6 for Discover cards In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card numbers. The algorithm is useful to determine whether a card number is entered correctly or whether a credit card is scanned correctly by a scanner. Credit card numbers are generated following this validity check, commonly known as the Luhn check or the Mod 10 check, which can be described as follows (for illustra- tion, consider the card number 4388576018402626): 1. Double every second digit from right to left. If doubling of a digit results in a two-digit number, add up the two digits to get a single-digit number. 4388576018402626 → 2 * 2 = 4 → 2 * 2 = 4 → 4 * 2 = 8 → 1 * 2 = 2 6 * 2 = 12 (1+ 2 = 3) → 5 * 2 = 10 (1+ 0 = 1) → 8 * 2 = 16 (1 + 6 = 7) → 4 * 2 = 8arrow_forwardQ1) Write a computer program that uses Newton's method to find the root of a given function, and apply this program to find the root of the following functions, using co as given. Stop the iteration when the error as estimated by n+1 - Enl is less than 10-6. Compare to your results for bisection. (a) f(x) = 1-2xe-/2, xo = 0; (b) f(x)=5-x-¹, x = ¹; (c) f(x)= x³ - 2x - 5, xo = 2; (d) f(x)=e-2, xo = 1; (e) f(x)=x-e, xo = 1; (f) f(x)=x-x-1, xo = 1; (g) f(x)=x²-sinx, xo =/; (h) f(x)= x³-2,0 = 1; (i) f(x) = x + tan x, zo = 3; (j) f(x)=2x-¹ In x, xo = 3.arrow_forward(proof by contraposition) If the product of two integers is not divisible by an integer n, then neither integer is divisible by narrow_forward
- C++ Programming: From Problem Analysis to Program...Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning