Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 6, Problem 6.5P
To determine
The relative compaction in the field.
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Homework #3
The results of a standard Proctor test are given in the following table.
a. Determine the maximum dry unit weight of compaction and the optimum
moisture content. Given: mold volume =943.3 cm'.
b. Determine the void ratio and the degree of saturation at the optimum moisture
content. Given: G, = 2.68.
Trial no.
Weight of moist soil in the mold (kg)
Moisture content (%)
1.78
5.0
1.87
7.5
3
1.95
10.0
4
1.98
12.5
5
2.02
1.97
15
17.5
7
1.90
20.0
b. Compute the plastic limit.
C. Compute the natural water content.
d. Compute the plasticity index.
e. Compute the liquidity index.
f. Compute the consistency index.
PROBLEM NO. 4
From the table shows a summary of a liquid limit and
plastic limit test.
LIQUID LIMIT TEST
Soil Wt. of wet Wt. of dry Water No. of
Sample Soil (kg) Soil (kg)
A.
Content Blows
9.5
6.7
28
B
7.95
5.54
20
8.21
5.69
18
D.
12.85
8.83
13
PLASTIC LIMIT TEST
Wt. of Dry
Soil(kg)
Soil
Wt, of Wet
Sample
Soil(kg)
9.05
7.35
2
8.66
7.01
Natural Water Content
Scil
Wt. of
Wt. of
Sample
Wet Soil
Dry Soi!
1
9.69
7.0
9.47
6.86
a. Compute the liquid limit.
b. Compute the plastic limit.
C. Compute the natural water content.
d. Compute the plasticity index.
e. Compute the liquidity index
GEOTECHNICAL ENGINEERING 1
1. The results of a standard Proctor test are given in the following table.
a. Determine the maximum dry unit weight of compaction and the optimum moisture content,
given that the Proctor mold volume is 1/30 ft³.
b. Determine the void ratio and the degree of saturation at the optimum moisture content
given G₁= 2.68.
Trial no.
1234567
Weight of moist soil in the mold (lb)
3.92
4.12
4.29
4.37
4.45
4.35
4.20
Moisture content (%)
5.0
7.5
10.0
12.5.
15
17.5
20.0
Chapter 6 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- 2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in mold Moisture (cu.m) (kg) (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture contentarrow_forwardA hydrometer test was conducted on the material passing sieve No, 200 and the results are listed in the table below, The results of sieve analysis on the soil showed that the percentage passing No. 4 was 90 % and that passing No. 200 was 20 %. Estimate the clay size fraction in the soil. Table : Results of hydrometer test diameter (mm) 0.0700 0.0400 0.0150 0.0020 % finer (combined) 19 finer 95 80 16 65 13 45 0.0010 30 6 Select one:arrow_forwardIn a sieve analysis test, 95.5% of the sample is passing the 5mm sieve and 5.13% is passing sieve #200, which of the following is correct about this sample: O There is no clay in the sample ) the percent of silt and clay is: 5.13% There is 4.5% Sand and Gravel in the sample O 95.5% of the sample is Sand and Silt O Oarrow_forward
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