(a)
Calculate the mean and standard deviation of violent television program viewers.
(a)
Explanation of Solution
The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:
Table 1
Viewers of violent shows | ||||||
X | 0 | 1 | 2 | 3 | 4 | 5 |
P(X) | 0.36 | 0.22 | 0.20 | 0.09 | 0.08 | 0.05 |
Viewers of nonviolent shows | ||||||
X | 0 | 1 | 2 | 3 | 4 | 5 |
P(X) | 0.15 | 0.18 | 0.23 | 0.26 | 0.10 | 0.08 |
The mean of number of correct answers among viewers of violent television programs is calculated as follows:
The mean value is 1.46.
The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:
The standard deviation is 1.49.
Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.
(b)
Calculate the mean and standard deviation of non-violent television program viewers.
(b)
Explanation of Solution
The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:
The mean value is 2.22.
The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:
The standard deviation is 1.45.
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Chapter 7 Solutions
Statistics for Management and Economics (Book Only)
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