Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
9th Edition
ISBN: 9781259989452
Author: Hayt
Publisher: Mcgraw Hill Publishers
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Chapter A1.2, Problem 4P
(a)
To determine
The Thevenin and Norton equivalent circuit by finding the open circuit value of
(b)
To determine
The value of the short circuit current for the given circuit.
(c)
To determine
The Thevenin equivalent resistance.
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The following questions pertain to the circuit shown on the previous page. The goal is obtain the current i∆ using nodal analysis. The voltage source common to the two nodes dictates that a supernode must be used.
A. What is the dependent source control parameter i∆ in terms of the node voltages?
B. Owing to the voltage source between nodes a and b, what is the constraint equation that relates va and vb? (Other than numeric values, your answer should contain only the terms vb and vb.)
C. What is the KCL equation for the supernode? (Your equation may contain both va and vb. Or, you are free to use the constraint equation to write the equation in terms of a single node voltage.) Using this equation or the ones previous, what is vb (give a numeric value.) What is i∆ (provide a numerical value).
Chapter A1 Solutions
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- For the circuit shown below, showing your work: 1. Find the VTH. Isc, and RTH Seen by R and draw Thevenin's equivalent circuit. 2. Use the Thevenin's equivalent circuit you obtained to find the values of VL when Rị is varied from 2.5k2 to 10.5k2 in steps of 1k2. Calculate Vi in each case. 3. Calculate the power PL absorbed by R in each case of Step 2. 4. Find the value of RL for maximum power transfer and the value of the maximum power from Step 3. 10k2 + 1k2 33k2 10V Ru22kO. 47KQ 5V b VTH Isc RTH Value RL 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5 10.5 (k2) VL (V) PL (mW) RL РМАХ Valuearrow_forwardSubject: Circuit INote:Support the problems with circuit diagram and label the pertinent partsWith full solutions pleasearrow_forward5. Intro to Circuits Learning Goal: This problem will help you practice labeling circuit elements and setting up KCL and KVL equations. Zes Vez Vas 5 lets (a) How many nodes does the above circuit have? Label them. Note: The ground node has been selected for you, so you don't need to label that, but you need to include it in your node count. (b) Notice that elements 1 - 6 and the voltage source V, have either the voltage across or the current through them not labeled. Label the missing voltages across or currents through for elements 1 - 6, and the voltage source V, so that they all follow passive sign convention. (e) Express all element voltages (including the element voltage across the source, V.) as a function of node voltages. This will depend on the node labeling you chose in part (a). (d) Write one KCL equation that involves the currents through elements I and 2. Hint: This will not be specific to your node labeling. Your answer may contain currents through other elements too.…arrow_forward
- 1.Show that the circuit is an equivalent circuit satisfied by the h-parameter equations. 2.Use the h-parameter equivalent circuit of (a) to find the voltagegain V2/Vg in the circuit , using the h-parameter values.arrow_forwardSupernode: In Figure below; the branch current through the 6 V source is certainly no known and cannot be directly expressed using Ohm's law 6 V 4 mA 6 mA 312 kn. To solve this problem, we recall that (N-1) linearly independent equations are required to determine the (N-1) nonreference node voltages in an N-node circuit. Since our network has three nodes (Le /N-3), we ned two lincarly independent equations. Now note that if somehow.one of the node.voltages is known, we immediately know the other (i.e., if K, is known, then FV-6. If V is known, then V=Vz+6, Therefore, the difference in potential between the two nodes is constrained by the voltage source and, hence, This constraint equation is one of the two linearly independent equations needed to determine the node voltages. Next consider the network in Figure below, in which the 6V source is completely enclosed within the dashed surface. kelivo Juper node 6 V 36 kn $12 k 4 mA The constraint equation governs this dashed portion of the…arrow_forwardR1 Click here for image ↑ ) 11 1+ Rm/ ↑) 2 In this circuit, R1 = 5 Q2, 11 = -6 A, 12 = 2 A, Rm = 8 Q. / has units of amperes. Determine the Thevenin equivalent circuit at terminals a-b. a CO State the values of the open-circuit voltage, Voc (in volts), and the equivalent resistance, Rth (in ohms), in the box below. Round your answers to one decimal place.arrow_forward
- Gonsider the following System 2 ]a a) inestyale the slablity of Hhe splem. b) investiyede Hhe anhrollability and obseruabi kty C) Fnd Hhe response Comesponding to { uc) =1 t>.} and xo)=[!) d) Do the obsenubility and Controllab lity af the sysfem change using the following hanspor makion.arrow_forwardELECTRICAL CIRCUITS LAB. FIRST YEAR Exp. No.: Exp. Name: Thevenin's theory Aim : To verify Thevenin's theorem. Theory : Thevenin's theorem as applied to (d.c )circuit may be stated as : (The current flowing through a load resistance (RL) connected across any two terminals A and B of any active network is given by Vth/Rth+RL Apparatus : 1. Power supply 10v. 2. One Ammeter. 3. One voltmeter 4. One ohmmeter. 5. Resistors 1.2kΩ, 390kΩ, 2.2kΩ , 820Ω. 630Ω Procedure : 1. Connect the circuit as shown in fig.(1) B 1.2 KA 390i 10% 820n v089 Fig(1) Switch the power supply on . 3. 2. Take the reading of ammeter and the voltage between A and B (IL, VL). Remove (RL) from the circuit and note the reading of (Vo.c). 5. 4. Remove power supply and makeshort and note the reading of ohmmeter (Rth) between A and B 6. Connect the Thevenin's equivalent circuit and note the reading of Ammeter and Voltmeter. 8arrow_forwardACTIVITY No. 6 Nodal Analysis ОВJECTIVE The study of nodal analysis is the objective of this exercise, specifically its usage in multi-source DC circuits. Its application to finding circuit currents and voltages will be investigated. THEORY OVERVIEW Multi-source DC circuits may be analyzed using a node voltage technique. The process involves identifying all of the circuit nodes, a node being a point where various branch currents combine. A reference node, usually ground, is included. Kirchhoff's Current Law is then applied to each node. Consequently a set of simultaneous equations are created with an unknown voltage for each node with the exception of the reference. In other words, a circuit with a total of five nodes including the reference will yield four unknown node voltages and four equations. Once the node voltages are determined, various branch currents and component voltages may be derived. EQUIPMENT (1) Adjustable DC Power Supply (1) Digital Multimeter (1) 4.7 k2 (1) 6.8 k2…arrow_forward
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