Activity 1B: Identical or Non-identical? Direction: Complete the table below by classifying the genotypes in Column 1 as homozygous dominant, heterozygous, or homozygous recessive basing on the allele combination given. Write your answers in column 2. An example is given for your guidance. GENOTYPE 1. HH 2. Rr CLASSIFICATION Homozygous dominant 3. aa 4. Dd 5. TT
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- O. exal B. Heredity Assume that dominant allele is B (brown eye color) and that recessive allele is b (blue eye color). Genotype of the father (male) is BB. Genotype of the mother (female) is Bb, Questions: 7. List all the possible genotypes and phenotypes and calculate the probability of each. 8. What is the probability of this couple having a child with brown eyes? What about blue eyes? Add Tip omment ASK Question Dow 5,288 66 APR 28 étv 260TOPIC : Genetics Example's for Question GENE = Hair Color ALLELE = Straight, Curly DOMINANCE = BB RECESSIVE = bb GENOTYPE = BB, Bb, bb PHENOTYPE = Blue, Black HOMOZYGOTE = BB (Blue eye), bb (Black eye) HETEROZYGOTE = Bb (Blue eye) MONOHYBRID = Aa DIHYBRID = AaBb TRIHYBRID = AaBbCc POLIHYBRID = AaBbCcDd MENDELLIAN GENETICS = Hair Color NON MENDELLIA = Blood Type QUESTIONS: Give Example of the following fo differentiate, DO NOT GIVE THE MEANING! (Follow the instructions above!) 1. MONOHYBRID CROSS = ? DIHYBRID CROSS = ? 2. BACK CROSS = ? TEST CROSS = ?Background Reminders: Dominant allele will express itself in the phenotype even when in combination with a different allele (recessive). Example: PP and Pp (purple flowers) Recessive allele does not express itself in the phenotype when combined with another allele (dominant) Example: pp (white flower) -> expressed only when recessive is by itself Problem 1- Autosomal Dominant: Widow’s peak (hairline) Having widow’s peak is a dominant trait (use W and w to represent alleles) A man who has a widow’s peak has a child with a woman that does not have widow’s peak. Their child does not have widow’s peak. What is the genotype of the father? _______________ B.) A man with widow’s peak (WW) has a child with a woman who does not have a widow’s peak. What is the probability their child will have a widow’s peak? ____________ Fill out this Punnett square: C.) If both parents are heterozygous for widow’s peak (Ww)… What is the probability…
- ne Left:1:41:03 GG Gg gg gG Abdelrahman Elgebaly: Attempt 1 Question 5 (Mandatory) (3 points) In fruit flies, gray body color is dominant over black body color. White eyes are dominant over red eyes. Using the letter G to represent body color and the letter W to represent eye color, what is the genotype of a heterozygous gray bodied, white- eyed fly? Write your answer below. Question 6 (Mandatory) (10 points) Saved Submit your Punnett Squares Lab Worksheet here. Paragraph V B I U A Ev Ev Punnett Squares Lab Worksheet.docx N S ►l| O % + v KY 8-Directions: Use the following information to answer the questions below: all are sex-linked recessive disorders. H= normal blood clotting C=Normal Vision h-hemophilia muscular dystrophy M= Normal c= colorblind 1. Write the genotypes for the following individuals: a. female with no family history of hemophilia b. male with hemophilia c. male with muscular dystrophy d. male with normal color vision e. normal color vision female with colorblind father f. male with normal blood clotting g. colorblind male m= 2. Cross a female who is a carrier of the gene for hemophilia with a man who has normal blood clotting. Tell the expected phenotypic ratio of the offspring. 3. Cross a female with normal color vision, but whose father was colorblind, with a man who has colorblindness. Tell the expected phenotypic ratio of the offspring. 4. Cross a woman who does not suffer from muscular dystrophy and has no family history of muscular dystrophy with a man who has the disorder. Tell the expected…I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. One form of red-green color blindness is an X-linked recessive trait. A heterozygote woman has children with a normal man. What is the percentage chance that they will have a child with color blindness?
- Match the word or phrase to a correct statement about it. recessive allele [Choose ] [Choose a cross between 4 parents an individual with 1 dominant allele and 1 recessive allele an individual with 2 recessive alleles a phenotype made of 2 dominant alleles only expressed in the phenotype if it's the only kind of allele present a letter written in uppercase dominant allele homozygous dominant a genotype made of 2 dominant alleles a cross looking at 2 separate genes dihybrid Choose | carrier an individual with 2 recessive 99+Explain your answer. Below is a pedigree showing the inheritance of colorblindness in Akoto family. Çolorblindness is a recessive and X-linked trait (X-). The allele for normal vision is dominant and is represented by Xe. 2 II IV 1. What are the genotypes of the founding parents (I-1, I-2)? 2. What is the percentage of the affected offspring (II)? 3. What is the phenotype of III-2? 4. Is the inheritance autosomal or sex-linked?I. Perform the indicated single-gene and two-gene crosses. Show all work. Show all Punnett squares. List the gene or genes involved, list and define all allele symbols, and indicate the genotypes of the individuals you are crossing above the Punnett square. Answer questions that ask for a ratio as a ratio and questions that ask for a percent as a percent. In humans, albinism is a recessively determined trait. One form of hereditary deafness is also a recessive trait. Show the cross of a man who is heterozygous for skin pigmentation and heterozygous for hereditary deafness with a woman who is albino and deaf. Show the expected phenotype ratio of the offspring.
- Explain the sex-linked traits. (S9LT-ld-29.4.4) Solve problems related to sex-linked traits. (S9LT-ld-29.4.4) WHAT I NEED (MATERIALS) • Worksheet • Pens WHAT TO DO (PROCEDURE) PART A Directions: Tell whether the following carry or show the sex-linke recessive spongy-tiny pores trait. Also, tell whether the individuals a male or female. Remember that since most sex-linked traits are recessive, the person w shows the trait can have no X's with big superscripted letters. So, if a m carries the trait, he must also show the trait. XDY XDXD XdY Carrier? (Yes or No) Has the Trait? (Yes or No) Male or Female Phenotype or Appearance of the Individual ided Questions: 1. What chromosomes will result to a normal phenotype (normal spongy po trait12PEDIGREES: Problem (continued) This pedigree shows the inheritance of cystic fibrosis in this family. I • QUESTIONS ••. 5. What is the genotype of individual II-3? Use the letter "f" to 1 2 represent the disease allele. II 1 2 3 6. Individuals II-I and II-2 are sisters. Explain how it is possible for one sister to have cystic fibrosis but NOT the other. III 1 2 3Match the following terms with their correct definition. A type of inheritance in which there is an earlier age of onset and a more severe phenotype in each successive generation. An effect in which the genotype of the mother determines the phenotype of the offspring. 1. Genetic anticipation 2. Position effect A type of inheritance were multiple genes contribute to the same phenotype. 3. Maternal effect 4. Pleiotropy A type of inheritance where one gene affects many different phenotypes. 5. Multigene (polygenic) inheritange An effect on gene expression from its location in an area of heterochromatin or euchromatin packaging.