Aquarium Fish - length: double - width: double - height: double fishes: Fish [ ] - name: String - type: String + Aquarium(1 :double, w : double, h : double, max:int) + getters //assume they exist, do not write them + volume( ): double + addFish( fish: Fish): void +getFish(i:int):Fish + searchFish(name: String, type: String): boolean + toString():String + Fish(name: String, type: String) + getName( ): String + getType( ): String + setName(name : String): void + setType(type : String): void + equals(fish : Fish) : boolean + toString():String 1. Create a class called Fish with data: name, and type. For example, a fish might have the name "Lisa" and of type "Catfish". This class also has the following methods: a constructor that initializes the data fields, getters, setters, toString, and a boolean method called equals used to check if two fish objects have the same name.

Microsoft Visual C#
7th Edition
ISBN:9781337102100
Author:Joyce, Farrell.
Publisher:Joyce, Farrell.
Chapter1: A First Program Using C#
Section: Chapter Questions
Problem 12RQ
icon
Related questions
Question
What is the solution for this question (using java language)
Consider the two classes represented in the following UML diagram.
Aquarium
Fish
- length: double
- width: double
- height: double
- fishes: Fish []
- name: String
- type: String
+ Aquarium(1 :double, w : double, h : double, max:int)
+ getters //assume they exist, do not write them
+ volume( ): double
+ addFish( fish: Fish): void
+getFish(i:int):Fish
+ searchFish(name: String, type: String): boolean
+ toString():String
+ Fish(name: String, type: String)
+ getName( ): String
+ getType( ): String
+ setName(name : String): void
+ setType(type : String): void
+ equals(fish : Fish) : boolean
+ toString():String
1. Create a class called Fish with data: name, and type. For example, a fish might have the name "Lisa"
and of type "Catfish". This class also has the following methods: a constructor that initializes the data
fields, getters, setters, toString, and a boolean method called equals used to check if two fish objects
have the same name.
Transcribed Image Text:Consider the two classes represented in the following UML diagram. Aquarium Fish - length: double - width: double - height: double - fishes: Fish [] - name: String - type: String + Aquarium(1 :double, w : double, h : double, max:int) + getters //assume they exist, do not write them + volume( ): double + addFish( fish: Fish): void +getFish(i:int):Fish + searchFish(name: String, type: String): boolean + toString():String + Fish(name: String, type: String) + getName( ): String + getType( ): String + setName(name : String): void + setType(type : String): void + equals(fish : Fish) : boolean + toString():String 1. Create a class called Fish with data: name, and type. For example, a fish might have the name "Lisa" and of type "Catfish". This class also has the following methods: a constructor that initializes the data fields, getters, setters, toString, and a boolean method called equals used to check if two fish objects have the same name.
Expert Solution
steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
Unreferenced Objects
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Microsoft Visual C#
Microsoft Visual C#
Computer Science
ISBN:
9781337102100
Author:
Joyce, Farrell.
Publisher:
Cengage Learning,
Systems Architecture
Systems Architecture
Computer Science
ISBN:
9781305080195
Author:
Stephen D. Burd
Publisher:
Cengage Learning