If the null hypothesis for an independent group t test is not supported, then the t test should be: O +1.00. a negative number. greater than ±1.00. 0.00.
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- Suppose we have the following table in our goodness of fit test results: Variable/Condition Value p-value 0.077 Significance level 0.05 Conclusion then what do we write in the cell corresponding to "Conclusion"? Suppose we have the following table in our goodness of fit test results: Variable/Condition Value p-value 0.077 Significance level 0.05 Conclusion then what do we write in the cell corresponding to "Conclusion"? We change the significance level to 0.95. We accept the null hypothesis that the disease possibly follows the specified mode of inheritance at the given gene. We reject the null hypothesis that the disease possibly follows the specified mode of inheritance at the given gene. We accept the null hypothesis that the disease almost certainly follows the specified mode of inheritance at the given gene. We collect more data.Considering that I have a chi-square test critical value of 3.84 what is the minimum X2 value for me to reject the null hypothesis? Is it 3.84 or 3.85?Assume that a Chi-square test was conducted to test the goodness of fit to a 9:3:3:1 ratio and a Chi-square value of 10.62 was obtained. Should the null hypothesis be accepted?
- 1) Chi-square analysis generates a p value, an important indicator of statistical support for a hypothetical outcome. If a p value = 0.05 > p > 0.01, the tested hypothesis fails to be falsified. Agree/Disagree? Answer with explanation here:Assume that a Chi-square test was conducted to test the goodness of fit to a 3:1 ratio and that a Chi-square value of 2.62 was obtained (Table value is equal to 3.84). Should the null hypothesis be accepted? How many degrees of freedom would be associated with this test of significance?If the chi-square value is 0 under the degree of freedom 1. What could be the interpretation and does it fit in the population of Hardy-Weinberg equilibrium?
- You repeatedly draw samples ofn= 100 from a population with a mean of 75 and a standard deviation of 4.5. What sample mean corresponds to az-score of 2.00?The confidence interval is reported as follows: Lower 95% CI < p < Upper 95% CI For this question you will be calculating the confidence interval but only reporting the Upper 95% CI using the Agresti-Coull Method. ( (you'll need to know the whole 95% CI for a future question) Do NOT use calculations from previous questions, this is a new scenario. In the Invisible Gorilla Experiment, 24 students were watching the video, only 7 noticed the gorilla. Calculate the 95% CI using the Agresti-Coull method, but only report the Upper 95% CI. Report your answer to 3 decimals.The calculated chi-square value which is 0 is less than the critical value which is 5.991 (under the degree of freedom 2). What is the probability of the computed chi-square value? And is it part of the population in Hardy-Weinberg equilibrium?
- If there is no difference between what is observed and what is expected, your chi-square value will be ________ . Group of answer choices impossible to determine 1 -1 0If the Chi-squared value for this system is 2.40, is.the population in Hardy-Weinberg equilibrium? Why? (note: the critical values for this test is 3.84). [Select]The mean weight of loaves of bread produced at the bakery where you work is supposed to be 1 pound. You are the supervisor of quality control at the bakery, and you are concerned that new employees are producing loaves that are too light. Suppose you weigh an SRS of bread loaves and find that the mean weight is 0.975 pound. What are the appropriate hypotheses for performing this significance test? Ho : x = 1; H. : x < 1 where i = the sample mean weight (in pounds) of bread loaves produced at the bakery. Ho : u = 1; H. : µ < 1 where u = the true mean weight (in pounds) of bread loaves produced at the bakery. Ho : µ < 1; H, : H = 1 where u = the true mean weight (in pounds) of bread loaves produced at the bakery. Ho : u = 1; H. : p = 0.975 where u= the true mean weight (in pounds) of bread loaves produced at the bakery. Ho : u = 1; H. : u # 1 where u= the true mean weight (in pounds) of bread loaves produced at the bakery.
