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- p-nitroaniline (2max : 375 nm) absorbs at a longer than Phitrobenzene (c) Explain why wavelength (hmax : 260 nm). (ij Write a short note on absorption. spectra complexes of charge transfer4G 4G illl 1:54 PM 43 ... 2. Name the following compounds: (c) CH3 CH3CHNH2 (a) (b) CH3CH2NHCH,CH3 N-CH3 (d) CH2CH3 (e) H CH3 H2NCH2CH2CHNH2Please provide the IUPAC name (only) for the compound that best represents the spectroscopic data here: • Molecular formula: C4H100 Important IR data (cm 1): 3280 (broad); 2910-2950 (many); 1053 • All 'H NMR data shown as x.xx ppm (splitting), integration. 1.23 ppm (t), 3 1.23 ppm (d), 3 "-OH" 1.46 ppm (m), 2 4.03 ppm (m), 1 5. PPM
- Given is teh mass spectogram of an unknown compoound. This unstable cyclic compund is a colorless liquid with a sharp odor and reacts with light and air with long exposure. What is the molar mass of the target mecule? What is the Molecular formula of the target molecule? What IHD /U ? What could be the description of the structure? Give the name of the structure.Complete the following answer using the data provided here: • Molecular formula: C5H10O2 • Important IR data (cm-1): 3150-3010 (many); 1740; 1248; 1050 • All 'H NMR data (ppm, splitting, integration): 3.66 ppm (s), 3; 2.20 ppm (t), 2; 1.80 ppm (m), 2; 0.98 ppm (t), 3 Which of the following best fit this spectroscopic data? OH H. A C D E6. (Chapter 15 - 47b) An aromatic compound, C9H12 has the following H NMR spectrum and a peak at 750 cmt in its IR spectrum. Answer the following questions. Chem. shift Rel. area 1.19 2.31 2.64 7.13 1.50 1.50 1.00 2.00 TMS 10 3 O ppm Chemical shift (6) 4(a). The IR peak at 750 cm in its IR spectrum indicate that the compound is. disubstituted = 4(b) The name of the compound is = Intensity-
- What compound is consistent with the NMR spectrum below? d6-DMSO solution F0.60 0.55 -0.50 -0.45 -0.40 -0.35 -0.30 -0.25 -0.20 -015 -0.10 -0.05 -0.00 0.05 6.5 5.5 5.0 4.5 4.0 6.0 f1 (ppm) 7.5 7.0 HOI HO. но но (A) (B) (C) (D) For8. Given the ¹H NMR spectrum provided, give the structure of the molecule. The IR shows two strong peaks at 1750 cm¹ and 3400 cm¹. The molecular formula is C3H6O2. Integrations are given below. —|- 10 1H 9 8 6 7 Chemical Shift (ppm) 1H 5 2H 3 2H 2CHEM 241L. Exp#12 NMR Spectre 3. Compound 3 is a low boiling liquid (bp-58°C) that reacts with Br. in CCl. to form a 1,1,2,2 tetra-bromide. Elemental Analysis: C-48.36%, II - 4.06%; contains halogen "C Spectral Data: 80.4ppm (doublet), 68.3ppm (singlet), 34.7ppm (triplet) Mass Spectrom Absorbence Intonally 48 'H NMR Infrared Spectrom 4000 3000 2500 2000 74 70 80 90 100 110 120 130 140 150 160 170 100 mie Wave Number, cm .1 1300 1200 1100 1000 mon 1600 Wavelength, microne Compound 3 Structure Ppin
- The leaves of the Brazilian Tree Senna multijunga contain a number of pryidine alkaloids that inhibit acetylcholinterinase. Two recentyl isolated isomeric compounds have the strcture have the strcture shown below. (NOTE: M=293) Use the mass spectral data provided to determine the precise location of the hydroxyl group in each isomer. Isomer A: EI-MS, m/z(rel. int): 222(20), 150(10), 136(25), 123(100) Isomer B:EI-MS, m/z(re;. int): 236(20), 150(10), 136(25), 123(100)Complete the following answer using the data provided here: Molecular formula: C4H8O2 Important IR data (cm-1): 3280 (broad); 2980-2730 (many); 1690; 1254 All 1H NMR data (ppm, splitting, integration): 11.0 ppm (s), 1; 2.57 ppm (m), 1; 1.07 ppm (d), 6 1. Sketch out a 1H NMR spectrum showing peak locations and peak splitting on a ppm scale for the data provided above. Include the data labels above in your spectrum, but do not show integration lines. 2. draw the most proper line bond structure for the data given aboveThe IR and NMR spectra of the material whose structure formula is C16H22O4 are given below.To this datawhat could be the ingredient?