Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 14, Problem 1E
Interpretation Introduction

Interpretation:

The comparison in the volumes of 1×1023 hydrogen molecules, 1×1023 oxygen molecules, and 2×1023 nitrogen molecules is to be stated.

Concept Introduction:

The ideal gas law is the compilation of Charles’s Law (VT), Boyle’s Law (V1P) and Avogadro’s Law (Vn). The ideal gas equation is shown below.

PV=nRT

Where,

P is the pressure.

V is the volume.

n is the number of moles.

R is gas constant.

T is temperature.

Expert Solution & Answer
Check Mark

Answer to Problem 1E

The volume of 1×1023 hydrogen molecules and 1×1023 oxygen molecules is same at the same temperature and pressure. The volume of 2×1023 nitrogen molecules is double the volume of 1×1023 hydrogen molecules and 1×1023 oxygen molecules at the same temperature and pressure.

Explanation of Solution

According to Avogadro’s Law, “volume of a gas is directly proportional to number of molecules at constant temperature and pressure.”

The number of molecules of hydrogen molecules and oxygen molecules is same. Therefore, the volume of 1×1023 hydrogen molecules and 1×1023 oxygen molecules is same at the same temperature and pressure.

The number of molecules of nitrogen molecules is double the number of mole of hydrogen molecules and oxygen molecules. Therefore, the volume of 2×1023 nitrogen molecules is double the volume of 1×1023 hydrogen molecules and 1×1023 oxygen molecules at the same temperature and pressure.

Conclusion

The volume of 1×1023 hydrogen molecules and 1×1023 oxygen molecules is same at the same temperature and pressure. The volume of 2×1023 nitrogen molecules is double the volume of 1×1023 hydrogen molecules and 1×1023 oxygen molecules at the same temperature and pressure.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
If 14.0 LL of hydrogen chloride gas reacts with 49.5 LL of oxygen gas, what is the volume of chlorine gas produced? Assume all gases are at the same temperature and pressure. HCl(g)+O2(g)→Cl2(g)+H2O(g)
What volume of hydrogen sulfide is required to produce 162 liters of sulfur dioxide according to the following reaction? (All gases are at the same temperature and pressure.) hydrogen sulfide (g) + oxygen(g) → water (1) + sulfur dioxide (g) Volume= L
It takes 3.500 in³ of mercury to make one manometer. Find the price of the mercury used to make 19 manometers by first calculating the cost of mercury for one manometer. What is the price of mercury used to make one manometer? What is the price of mercury used to make 19 manometers?

Chapter 14 Solutions

Introductory Chemistry: An Active Learning Approach

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY