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In solving problems and examining examples, you probably have noticed some recurring forms:
w = 12γbt = (12γt)b = a1b
(F1)a = FabCpCv = (FaCpCv)b = a0b
(F1)a – F2 = 2T/d = 33 000Hd/V = 33 000 HnomKsnd/V
F2 = (F1)a –[(F1)a – F2] = a0b – 2T/d
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Chapter 17 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
- From the image below, and using the given datum, match the variable expressions to their position coordinates, SA, SB and SC, where s A is for block A, $3 is for pulley B, and so is for pulley C. If an expression does not match any position coordinate, then match it to the "None" option. 1.k-q 2.0 3.p 4. k SA Datum bc SC k ✓ None SB ФВ A Р ⒸOFarrow_forwardEFx=0= (0.433 F1) - (0.667 F2) - (0.866 F3) + (0.342 P) EFy=0= - (0.250 F1) + (0.667 F2) EFz=0= (0.866 F1) + (0.333 F2) + (0.500 F3) - (0.940 P) Find the magnitude of F1, F2, and F3arrow_forwardYou are the mechatronics engineer of a manufacturing plant. You decide to perform an analysis on a robot arm of the assembly line with the objective of optimizing its performance. After taking several readings of the speed of the arm’s end effector, you approximate its velocity to the function given below. v(t) = -t4 + 5t3 - 7t2 + 3t + 0.22 0 =< t =< 3 where the velocity is in ms-1 d) Knowing that the distance travelled by an object is the area under its velocity-time graph, determine the distance travelled by the end effector on the interval 0 =< t =< 1 by using the mid-ordinate rule. Simpson’s rule correct to 3 decimal places using four intervals. e) Calculate the same distance as in (d) above by using the appropriate definite integral. f) Compare the distances you calculated in (d) and (e) above and comment on the accuracy of the two methods you used in (d)arrow_forward
- You are the mechatronics engineer of a manufacturing plant. You decide to perform an analysis on a robot arm of the assembly line with the objective of optimizing its performance. After taking several readings of the speed of the arm’s end effector, you approximate its velocity to the function given below. v(t) = -t4 + 5t3 - 7t2 + 3t + 0.22 0 =< t =< 3 where the velocity is in ms-1 Use your knowledge of differentiation to sketch the velocity-time graph, clearly marking the critical points. Using the graph sketched in (a) above, estimate the velocity when t = 1.5 s Calculate the velocity of the function when t = 1.5 s by substituting to the velocity function. Compare this value to the value you estimated in b above.arrow_forwardmathlab code: %Press-Fit Example Problem 117 %Steel, psi ES=30*10^6 MuS=0.292; %Cast Iron EC=14.5*10^6; MuC=0.211; di=0; d0=2.002; Di=2.000; D0=3.000; % tolerance tol=d0-D0; % Pressure Eq. (3-56) R=Di/2; r0=D0/2; ri=di/2; Hub=(1/ES)*((r0^2+R^2)/(r0^2-R^2)+MuS); Inner=(1/EC)*((R^2+ri^2)/(R^2-ri^2)-MuC); p=tol/(R*(Hub+Inner))arrow_forwarduo 9:1 * Iln. Classroom > docs.google.com a QV In the toggle mechanism, as shown in Figure, the slider D is constrained to move on a horizontal path. The crank OA is rotating in the counter-clockwise direction at a speed of 180 r. p.m. The dimensions of various links are as follows : OA = 180 mm, CB = 240 mm. AB = 360 mm, and BD = 540 mm. By using Relative Velocity Method, find : 1. Velocity of slider D, 2. Angular velocity of links AB, CB and BD. A 45° 360 mm 105 mm DE إجابتك Q3/ What are the most important factors * ?that determine the quality of the belt إجابتك Q2/ An enaine shaft runnina at 190 r.p.m. is + -> 44 ...arrow_forward
- The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093arrow_forward$+2.5$41 543834 2 8 b. A student has written a mathematical model for a rotational mechanical system without gears and some data were missing as shown below: [4s² + 2s +5 -25 as 0 -2s 3s² + 4s +6 -(1+B) 0 -6 3s +6 [0₁(s)] 0₂ (s 03(s)] What are the values of a and B? 2. What is the degree of freedom of the system? Sketch the expected rotational mechanical system and show thetorque, angular displacements and all values of inertias, springs, and dampers on the sketch with 85²2445445+8 their units. (89² +2+5+8) (33+4)arrow_forwardQ4/ For the figure below:* a) gFy is: 0 0 0 0 0 0 C 0.6m 0 0 0 0 0 0 C 0.2 O-860.12 F2=1000 N -824.59 0 0 0 0 0 0 0 -831.64 -900 -789.22 - 840.88 Q4/b) EFx is: * Other: O-525.146 -521.46 -510.2 490.54 -499.54 -515.32 0 Other: Q4/C) The resultant R is * 977.6 983.57 950.21 945.54 960.24 965.22 400 Other: 0.8m F1=1600N 0.4 4 F3=900 N 3 F4=1200N Q4/d) The resultant direction is 0 0 0 0 0 0 0 0 58 60 65 54 50 52 63 Other:arrow_forward
- Read the peak power and peak torque from the following curve. Also, find the engine speed that the peak power and peak torque occur at, and ensure this engine speed is in Rad/sec. Torque Power N.m kW 40 35 30 25 8020 70 6015 50 40 10 30 20 5 10 00 0 1000 N (C max) N(C min) N (Pmax) 2000 3000 4000 5000 6000 Engine Speed (RPM) g/kWh 400 300 200 100 0 Specific Fuel Consumptionarrow_forwardQ4/ For the figure below:* a) EFy is: 0 0 0 0 0 0 C 0.6m 0 0 0 0 0 0 C 0.2 O-860.12 F2=1000 N -824.59 -831.64 0 0 0 0 0 0 0 -900 -789.22 - 840.88 Q4/b) EFx is: * Other: O-525.146 O-521.46 -510.2 490.54 -499.54 -515.32 0 Other: Q4/C) The resultant R is * 977.6 983.57 950.21 945.54 960.24 965.22 400 Other: 0.8m F1=1600N +0.4 4 F3=900 N 3 F4=1200N Q4/d) The resultant direction is 0 0 0 0 0 0 0 0 58 60 65 54 50 52 63 Other:arrow_forward2:45 ull 4G A moodle1.du.edu.om 1- A J-Type thermocouple referenced to 80°F has a measured output emf of 2.878 mV. What is the temperature of the measuring junction? 2- Assume that the measured temperature is 250° F, what should be the output voltage if the reference temperature is 90 °F. RK: if the temperature values are not in the table, you have to use interpolation. Response to question 2: The measured output voltage (mV) Select one: O a. 2.764 b. 4.769 c. 5.762 O d. 3.768arrow_forward
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