Chapter 18, Problem 18.57SP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of excess of ${\text{O}}_2$ with $\text{Ca}$ has to be written.

Concept Introduction:

Reactivity of Oxygen:

The reactivity of an Oxygen can be anticipate from its electronic configuration $\left({\text{1s}}^{\text{2}}{\text{2s}}^{\text{2}}{\text{2p}}^{\text{4}}\right)$.  Oxygen has shortage of two electron to form octet configuration of neon, the next noble gas.  Oxygen can attain octet configuration either by gaining two electrons from an active metals such as Lithium and Magnesium to form ionic oxide and covalent oxide (${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}$ and ${\text{SO}}_{\text{3}}$) with non-metals.

(b)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of excess of ${\text{O}}_2$ with Carbon has to be written.

Concept Introduction:

Reactivity of Oxygen:

The reactivity of an Oxygen can be anticipate from its electronic configuration $\left({\text{1s}}^{\text{2}}{\text{2s}}^{\text{2}}{\text{2p}}^{\text{4}}\right)$.  Oxygen has shortage of two electron to form octet configuration of neon, the next noble gas.  Oxygen can attain octet configuration either by gaining two electrons from an active metals such as Lithium and Magnesium to form ionic oxide and covalent oxide (${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}$ and ${\text{SO}}_{\text{3}}$) with non-metals.

(c)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of excess of ${\text{O}}_2$ with $\text{As}$ has to be written.

Concept Introduction:

Reactivity of Oxygen:

The reactivity of an Oxygen can be anticipate from its electronic configuration $\left({\text{1s}}^{\text{2}}{\text{2s}}^{\text{2}}{\text{2p}}^{\text{4}}\right)$.  Oxygen has shortage of two electron to form octet configuration of neon, the next noble gas.  Oxygen can attain octet configuration either by gaining two electrons from an active metals such as Lithium and Magnesium to form ionic oxide and covalent oxide (${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}$ and ${\text{SO}}_{\text{3}}$) with non-metals.

(d)

Interpretation Introduction

Interpretation:

The balanced equation for the reaction of excess of ${\text{O}}_2$ with Boron has to be written.

Concept Introduction:

Reactivity of Oxygen:

The reactivity of an Oxygen can be anticipate from its electronic configuration $\left({\text{1s}}^{\text{2}}{\text{2s}}^{\text{2}}{\text{2p}}^{\text{4}}\right)$.  Oxygen has shortage of two electron to form octet configuration of neon, the next noble gas.  Oxygen can attain octet configuration either by gaining two electrons from an active metals such as Lithium and Magnesium to form ionic oxide and covalent oxide (${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}$ and ${\text{SO}}_{\text{3}}$) with non-metals.