Interpretation:
The given equation is to be balanced in the basic medium by the half-reaction method.
Concept introduction:
In the half-reaction method of balancingachemical reaction, the
The following are the steps to balance the chemical equation in the basic medium:
Step 1: Write the skeleton equationin ionic form.
Step 2: Separate the unbalanced reaction into half reactions.
Step 3: Balance the number of oxidized and reduced atomsso that both the sides have the same oxidation state. This is done by adding electrons to the more positive side to make it equal to the less positive side of the half-reaction.
Step 4: Balance the charge so that both sides have the same total charge by adding an OH- ion to the side deficient in the negative charge.
Step 5: Balance the oxygen atoms by adding
Step 6: Make the electron gain equivalent to the electron loss in the oxidation half reactions and reduction half reactions.
Step 7: Combine the two half reactions together.
Step 8: Remove chemical species of asimilar kind, if any, and write the simplified chemical equation.
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Chemistry
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- Table 20.2 Half-reaction Ee (V) Cr3+ (aq) + 3e- ¬ Cr (s) -0.74 Fe2+ (aq) + 2e- - Fe (s) -0.440 Fe3+ (aq) + e- ¬ Fe2+ (s) +0.771 Sn4+ (aq) + 2e- - Sn2+ (aq) +0.154 ?Which of the following reactions will occur spontaneously as written Sn4+ (aq) + Fe2+ (aq) – Sn2+ (aq) + Fe (s) .a 3FE2+ (aq) - Fe (s) + 2Fe3+ (aq) .b O 3Fe (s) + 2Cr3+ (aq) - 2Cr (s) + 3FE2+ (aq) .c O 3Sn4+ (aq) + 2Cr (s) - 2Cr3+ (aq) + 3Sn2+ (aq) .d O Sn4+ (aq) + Fe3+ (aq) - Sn2+ (aq) + Fe2+ (aq) .e Oarrow_forwardWhen the following redox reaction is correctly balanced: Br + CrO42- BrO3 + Cr(OH)3 (s) (basic) what is the coefficient in front of CrO4 2- ? O 2 O 3 O 1 O 10 6arrow_forwardBalance the following redox equations: CrO42- + Fe2+ —> Cr3+ + Fe3+ (in acidic solution) MnO4- + ClO2- —> MnO2 + ClO4- (in basic solution)arrow_forward
- For each of the following balanced half-reactions, determine whether an oxidation or reduction is occurring.(a) Fe3+ + 3e− ⟶ Fe(b) Cr ⟶ Cr3+ + 3e−(c) MnO42− ⟶ MnO4− + e−(d) Li+ + e− ⟶ Liarrow_forwardComplete and balance the following half-reaction in acidic solution MnO4 (aq) → MnO2(s) 14- 3- 12- 12+ 3+ 14+ 1 3 4 7 8. Os Os O, 14 6. 7 8. (s) (1) (g) (aq) OH e H+ H2O Mn H. H3O+ ↑arrow_forwardSkeletal Equation Co³+ (aq) + Mn²+ (aq) → Co²+ (aq) + Mn++ (aq) Which of the following half-reactions is correct for the cobalt(III)/cobalt(II)? Select one: O Co³+ (aq) → Co²+ (aq) + 1e- O Co³+ (aq) + 1e - Co²+ (aq) O Co³+ (aq) le Co²+ (aq) O Co³+ (aq) → Co²+ (aq) - 1e- In Question 14, the cobalt(III) undergoes Refer again to the skeletal equation shown in Question 14. Which of the following half-reactions is correct for the manganese(II)/manganese(IV)? Select one: O Mn²+ (aq) Mn4+ (aq) 2e- O Mn²+ (aq) - 2e- → Mn4+ (aq) O Mn²+ (aq) + 2e → Mn¹+ (aq) O Mn²+ (aq) → Mn4+ (aq) + 2e- ♦ In the skeletal equation in Question 14, the manganese(II) is undergoing Select one: O oxidation O reductionarrow_forward
- How long will it take to plate out each of the following with a current of 103.7 A? (a) 2.9 kg Al from aqueous Al3+ (b ) 3.3 g Ni from aqueous Ni2+ (c) 5.9 mol Ag from aqueous Ag +arrow_forwardFor the redox reaction given below complete the following: Fe + Mn203---> Fe203 + MnO (a) What is the oxidation no. of Mn in Mn2O3? +3 (b) What is the oxidation no. of Fe +3 (c) Find the element oxidized Fe (d) Find the element Reduced Mn (e) Find the Oxidizing Agent Mn203 (f) Find the Reducing Agent Fe (g) How many electrons transferred in this reaction? Choose... +arrow_forwardQuestion 22 Consider the galvanic cell shown below (the contents of each half-cell are written beneath each compartment): Pt Cr 0.50 MB12 0.20 MC 0.10 MBr" The standard reduction potentials are as follows: Cr"(ag) + 3e- Cr(s) Bry(ag) + 2e- 2Br (aq) --0.73 =+1.09 V Which of the following statements about this cell is false? This is a galvanic cell. Electrons flow from the Pt electrode to the Cr electrode O Reduction occurs at the Pt electrode. O The cell is not at standard conditions. O To complete the crcuit, cations migrate into the left half-cell and anions migrate into the right half-cell from the salt bridge.arrow_forward
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