Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 9, Problem 3P
To determine
The additional revolutions required by the disk to reach an angular speed of
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Chapter 9 Solutions
Physics for Scientists and Engineers
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- Figure P10.18 shows the drive train of a bicycle that has wheels 67.3 cm in diameter and pedal cranks 17.5 cm long. The cyclist pedals at a steady cadence of 76.0 rev/min. The chain engages with a from sprocket 15.2 cm in diameter and a rear sprocket 7.00 cm in diameter. Calculate (a) the speed of a link of the chain relative to the bicycle frame, (b) the angular speed of the bicycle wheels, and (c) the speed of the bicycle relative to the road, (d) What pieces of data, if any, are not necessary for the calculations?arrow_forwardA disk 8.00 cm in radius rotates at a constant rate of 1200 rev/min about its central axis. Determine (a) its angular speed in radians per second, (b) the tangential speed at a point 3.00 cm from its center, (c) the radial acceleration of a point on the rim, and (d) the total distance a point on the rim moves in 2.00 s.arrow_forwardA turntable (disk) of radius r = 26.0 cm and rotational inertia0.400 kg m2 rotates with an angular speed of 3.00 rad/s arounda frictionless, vertical axle. A wad of clay of mass m =0.250 kg drops onto and sticks to the edge of the turntable.What is the new angular speed of the turntable?arrow_forward
- A bicycle is turned upside down while its owner repairs a flat tire on the rear wheel. A friend spins the front wheel, of radius 0.381 m, and observes that drops of water fly off tangentially in an upward direction when the drops are at the same level as the center of the wheel. She measures the height reached by drops moving vertically (Fig. P10.74 on page 332). A drop that breaks loose from the tire on one turn rises h = 54.0 cm above the tangent point. A drop that breaks loose on the next turn rises 51.0 cm above the tangent point. The height to which the drops rise decreases because the angular speed of the wheel decreases. From this information, determine the magnitude of the average angular acceleration of the wheel.arrow_forwardDuring a certain time interval, the angular position of a swinging door is described by = 5.00 + 10.0t + 2.00t2, where is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0 and (b) at t = 3.00 s.arrow_forwardA record rotates through 5.6 radians as it slows down uniformly from 78.0rpm to 22.8 rpm. What is the magnitude of the angular acceleration of the record?arrow_forward
- A motor increases its speed from 100 rev/min to 500 rev/min in 20 seconds. If this is done with a constant angular acceleration, how many revolutions occur in this 20 s interval? 6000 rev O 170 rev O 67 rev O 100 rev O 200 revarrow_forwardA disk with a diameter of 30 cm speeds up from 20 rad/s to 40 rad/s in 20s. (a) How many revolutions will the disk go through during that time period? (b.) What is the average linear acceleration of the disk? A 96 rev; 0.30 m/s^2 B) 96 rev; 0.15 m/s^2 c) 85 rev; 0.30 m/s^2 85 rev; 0.15 m/s^2arrow_forwardA shaft of a motor rotates 1800rpm. Through how many radians does it turn in 18 seconds? 3402 rad A golf club strikes a golf ball. The club and the ball remains in contact for 0.6ms. The 35gram ball leaves the club with a speed 60m/s. Calculate the average force of the club to the ball. Your answer car Police investigator observes a skid marks 25m long left by a 1500kg Fficiont ofarrow_forward
- A belt is pulled to the right between cylinders A and B . Knowing that the speed of the belt is a constant 5 ft/s and no slippage occurs, determine (a) the angular velocities of A and B ,(b) the accelerations of the points which are in contact with the belt.arrow_forwardThe crankshaft in a race car goes from rest to 3000 rpmrpm in 3.5 ss. What is the angular acceleration of the crankshaft? How many revolutions does it make while reaching 3000 rpmrpm?arrow_forwardPoint A of the circular disk is at the angular position 0 = 0 at time t = 0. The disk has angular velocity wo = 0.29 rad/s at t = 0 and subsequently experiences an angular acceleration a = 1.8t where t is in seconds, and a is in radians per second squared. Determine the velocity and acceleration of point A in terms of fixed i and j unit vectors at time t = 2.7 s. Assumer = 145 mm. α Answers: VA = aд = 90 (i ( i 0 6.806 i + i + i i 1 0.705 j) m/s j) m/s²arrow_forward
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