Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
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Chapter 1, Problem 1.42P
To determine
The peak values of input sinusoid are required to produce output at different given edges.
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The term duty cycle refers to the amount of time a signal is
complete cycle.
A. off
compared to the period of one
B. on
The output voltage of op-amp is positive saturation, when the voltage applied to the
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A. inverting
B. noninverting
A square wave that is 20V at its high state and OV when it is off will produce an average DC
when its duty cycle is 75%. Formula: VOUT = Duty Cycle * Peak voltage
voltage of
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B. 10V
C. 15V
Design an amplifier that provides 2.5 W of signal power to a 50 N load resistance. The signal
source provides a 20 mV rms signal and has a resistance of 1 MN. Three types of voltage
amplifier stages are available:
a) A high-input-resistance type with Rin = 1MN, Apo = 10, and Rout = 10k.
b) A high-gain type with Rin = 10kN, Apo = 100 and Rout = 1kn.
c) A low-output-resistance type with Rin = 10kn, Apo = 1 and Rout = 200.
Design a suitable amplifier using a combination of these stages. The design should have the
minimum number of stages and ensure that the signal level is not reduced below 10 mV at any
point in the amplifier chain. Find the load voltage and power output realized.
(1)
Describe in detail the relative advantages of Class A and Class B
amplifiers. In what types of circuits would Class B be advantageous
over Class A
(1I) With the aid of signal diagrams, describe two forms of distortion you
would expect to observe on an output signal of a Class B amplifier.
(III) Describe in circuit terms the advantages of a Class AB amplifier.
Chapter 1 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 1.1 - Prob. 1.1ECh. 1.1 - Prob. 1.2ECh. 1.1 - Prob. 1.3ECh. 1.1 - Prob. 1.4ECh. 1.2 - Prob. 1.5ECh. 1.2 - Prob. 1.6ECh. 1.2 - Prob. 1.7ECh. 1.2 - Prob. 1.8ECh. 1.3 - Prob. 1.9ECh. 1.4 - Prob. 1.10E
Ch. 1.4 - Prob. 1.11ECh. 1.5 - Prob. 1.12ECh. 1.5 - Prob. 1.13ECh. 1.5 - Prob. 1.14ECh. 1.5 - Prob. 1.15ECh. 1.5 - Prob. 1.16ECh. 1.5 - Prob. 1.17ECh. 1.5 - Prob. 1.18ECh. 1.5 - Prob. 1.19ECh. 1.5 - Prob. 1.20ECh. 1.5 - Prob. 1.21ECh. 1.6 - Prob. 1.22ECh. 1.6 - Prob. D1.23ECh. 1.6 - Prob. D1.24ECh. 1 - Prob. 1.1PCh. 1 - Prob. 1.2PCh. 1 - Prob. 1.3PCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. D1.8PCh. 1 - Prob. D1.9PCh. 1 - Prob. 1.10PCh. 1 - Prob. D1.11PCh. 1 - Prob. D1.12PCh. 1 - Prob. D1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. D1.49PCh. 1 - Prob. D1.50PCh. 1 - Prob. D1.51PCh. 1 - Prob. D1.52PCh. 1 - Prob. 1.53PCh. 1 - Prob. 1.54PCh. 1 - Prob. 1.55PCh. 1 - Prob. 1.56PCh. 1 - Prob. D1.57PCh. 1 - Prob. 1.58PCh. 1 - Prob. D1.59PCh. 1 - Prob. D1.60PCh. 1 - Prob. D1.61PCh. 1 - Prob. D1.62PCh. 1 - Prob. 1.63PCh. 1 - Prob. 1.64PCh. 1 - Prob. 1.65PCh. 1 - Prob. 1.66PCh. 1 - Prob. 1.67PCh. 1 - Prob. 1.68PCh. 1 - Prob. 1.69PCh. 1 - Prob. D1.70PCh. 1 - Prob. 1.71PCh. 1 - Prob. 1.72PCh. 1 - Prob. 1.73PCh. 1 - Prob. 1.74PCh. 1 - Prob. D1.75PCh. 1 - Prob. D1.76PCh. 1 - Prob. 1.77PCh. 1 - Prob. 1.78PCh. 1 - Prob. D1.79PCh. 1 - Prob. 1.80PCh. 1 - Prob. 1.81P
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