Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 1, Problem 1.45P
To determine
The overall voltage gain. Also, the loss in gain, gain after the source is connected directly to the load and the ratio of these two gains.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Suppose we have a resistive load that varies from 5 kΩ to 10 kΩ .We connect this load to an amplifier, and we need the voltage across the load to vary by less than 1 percent with variations in the load resistance. What parameter of the amplifier is important in this situation? What range of values is allowed for the parameter?
The input signal Vin shown in the figure is a 1 kHz
square wave voltage that alternates between
+7 V and -7 V with a 50% duty cycle. Both
transistor have the same current gain which is
large. The circuit delivers power to the load
resistor R₁. What is the efficiency of this circuit for
the given input? choose the closest answer.
+10 V
V..
in
- 10 V
R,=10 Ω
"Given a common emiiter amplifier (Voltage Divider) with the following network: R1 = 22k, R2 = 6.8k, Rc = 1k, Re = 560, Beta = 150, Vcc = 12V. The load resistance RI = 10k. The output impedance is
Note: R2 is the resistor connected to the base and ground."
O 909 ohms
O 833 ohms
O 1000 ohms
O 732 ohms
O 1245 ohms
O "10,000 ohms"
Chapter 1 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 1.1 - Prob. 1.1ECh. 1.1 - Prob. 1.2ECh. 1.1 - Prob. 1.3ECh. 1.1 - Prob. 1.4ECh. 1.2 - Prob. 1.5ECh. 1.2 - Prob. 1.6ECh. 1.2 - Prob. 1.7ECh. 1.2 - Prob. 1.8ECh. 1.3 - Prob. 1.9ECh. 1.4 - Prob. 1.10E
Ch. 1.4 - Prob. 1.11ECh. 1.5 - Prob. 1.12ECh. 1.5 - Prob. 1.13ECh. 1.5 - Prob. 1.14ECh. 1.5 - Prob. 1.15ECh. 1.5 - Prob. 1.16ECh. 1.5 - Prob. 1.17ECh. 1.5 - Prob. 1.18ECh. 1.5 - Prob. 1.19ECh. 1.5 - Prob. 1.20ECh. 1.5 - Prob. 1.21ECh. 1.6 - Prob. 1.22ECh. 1.6 - Prob. D1.23ECh. 1.6 - Prob. D1.24ECh. 1 - Prob. 1.1PCh. 1 - Prob. 1.2PCh. 1 - Prob. 1.3PCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. D1.8PCh. 1 - Prob. D1.9PCh. 1 - Prob. 1.10PCh. 1 - Prob. D1.11PCh. 1 - Prob. D1.12PCh. 1 - Prob. D1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. D1.49PCh. 1 - Prob. D1.50PCh. 1 - Prob. D1.51PCh. 1 - Prob. D1.52PCh. 1 - Prob. 1.53PCh. 1 - Prob. 1.54PCh. 1 - Prob. 1.55PCh. 1 - Prob. 1.56PCh. 1 - Prob. D1.57PCh. 1 - Prob. 1.58PCh. 1 - Prob. D1.59PCh. 1 - Prob. D1.60PCh. 1 - Prob. D1.61PCh. 1 - Prob. D1.62PCh. 1 - Prob. 1.63PCh. 1 - Prob. 1.64PCh. 1 - Prob. 1.65PCh. 1 - Prob. 1.66PCh. 1 - Prob. 1.67PCh. 1 - Prob. 1.68PCh. 1 - Prob. 1.69PCh. 1 - Prob. D1.70PCh. 1 - Prob. 1.71PCh. 1 - Prob. 1.72PCh. 1 - Prob. 1.73PCh. 1 - Prob. 1.74PCh. 1 - Prob. D1.75PCh. 1 - Prob. D1.76PCh. 1 - Prob. 1.77PCh. 1 - Prob. 1.78PCh. 1 - Prob. D1.79PCh. 1 - Prob. 1.80PCh. 1 - Prob. 1.81P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- What is the voltage gain of the circuit? (V out / V in =?)arrow_forwardFor the circuit below, Assume constant-voltage model VD,on =800 mV and VB=1.4 V. In this circuit, Vin is increased from 0 to a finite value. At what value of Vin, does D1 starts to conduct? What is the current of resistor R1= 2kΩ, if Vin=5 V? What is the output voltage, Vout, if Vin=5 V? What is the voltage across R1 if Vin = 5 V? What is the current of resistor R1= 2kΩ, if Vin=1.8 V? What is the output voltage, Vout, if Vin=1.8 V?arrow_forward1. The 10M resistor (all resistor values are in Ohms and M = million) represents a scope input resistance. Calculate the voltage across the 2M resistor and compare (% error) to the ideal case. An ideal scope input resistance is the same as an ideal internal resistance of a voltmeter. 15V dc 100k 2M 10M Replace the 2M resistor with a 100K resistor and calculate the voltage across the 100K resistor and compare (% error) to the ideal case. For which resistor value (2M or 100K) does the scope have the greatest “loading” effect? Justify your answer.arrow_forward
- In the circuit shown in the figure, the operational amplifier is ideal. Accordingly, how many volts is the V0 output voltage in the circuitarrow_forwardV D VDD =2V R = 4KQ Rp2 Rpl R, = 4KQ RPL = 4KO. Rp2 = 4KQ RS = 4KQ R1 gut M2 Cp2 M1 Vin Co R$2 Rs2 = 6KQ Rs1 R2 Vss = 0 V Figure 5arrow_forward4. A current measuring operational amplifier is made by bridging a resistor across the inverting terminal (pin 2) and the output terminal (pin 6). The noninverting terminal is grounded. a. Draw a sketch of the current measuring circuit. Determine an appropriate resistor for converting a current of 1.0 picoamperes (1.0 × 10-¹2 A) to a voltage of 0.010 V. (The math for this question is very easy, don't overthink this question. b. There are a few reasons that circuit you drew in part a will not be effective. First, you will have a difficult time finding a resistance with the required resistance value. Second, the input terminals do not have infinite resistance value. In fact, for an inexpensive 741 op-amp, the input terminal resistance may only be a few MOhms, which is far less than the resistance your calculated for the feedback resistor. This means that more current will be drawn into the op-amp than will go around it. Finally, the op-amp may have a bias current that is larger than the…arrow_forward
- 3. For the power amplifier circuit in Figure A: a) Calculate the power input and power output if the input signal results in a base current of 5 mA. b) Calculate the input power dissipated by the circuit if RB is changed to 2.2kn. c) Find the maximum output power that can be delivered by the circuit if RB is changed to 3 kQ? Vcc = 20 V Rg I kQ Rc = 20 2 B = 25arrow_forwardFigure below shows a circuit with 3 amplifiers. Answer all the questions.arrow_forwardThe exercise question is: find the voltage gain and input resistance to the following circuit. Second, explain why no current flows through the 20 kOhm resistor that is connected to ground.arrow_forward
- According to the figure below, the gain has no effect on the output (2) ihä: . .voltage value when IT R; R1 VINI OW A R2 VIN2 OW O V oVOUT the value of R1 equal to Rf O all the resistors have different values the value of R2 equal to Rf only R1 and R2 have same values all the resistors have same valuesarrow_forward6. Let us consider the following circuit: 2R www 2²R www N-input V1- V2- 2NR VN VN. (a) Find V as a function of V₁, V₂, out (b) What is this circuit's function? (Hint: look up digital-to-analog conversion) R ww R www R www -Voutarrow_forwardVsource Rsource Rin ww 175V b) the voltage across the load resistor iin + Vin Avo i out w -Ro R₁oad + + Vload An amplifier has the following characteristics: Rin = 5 kn, Ro= 300 Q and Ayo = 35. If it is connected to a 0.2 V source with a series resistance of 100 2 at the input and a load resistor of 2 k at the output, determine a) the overall voltage gain, G,arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSON
Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Programmable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill Education
Electric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSON
Engineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,
What is a Power Amplifier, And Do I Need One?; Author: Sweetwater;https://www.youtube.com/watch?v=2wkmSm4V00M;License: Standard Youtube License