General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 27, Problem 15E
(a)
To determine
The wavelength of electrons.
(b)
To determine
The energy of electrons.
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The resolving power of a microscope depends on the wavelength used. If you wanted to “see” an atom, a wavelength of approximately 1.00 × 10-11 m would be required. (a) If electrons are used (in an electron microscope), what minimum kinetic energy is required for the electrons? (b) What If? If photons are used, what minimum photon energy is needed to obtain the required resolution?
simple cubic crystal is cut so that the rows of atoms on its surface are separated by adistance of 0.352 nm. A beam of electrons is accelerated through a potential difference of 175 Vand is incident on the surface. If all diffraction orders are possible, at what angles, relative to thecrystal surface, would the diffracted beams be observed? me = 9.11 ×10 -31 kg.
The planes of atoms in a particular cubic crystal lie parallel to the surface, 0.80 nm apart. X rays having wavelength 0.50 nm are directed at an angle θ to the surface. (a) For what values of θ will there be a strong refl ection? (b) What energy electrons could give the same result?
Chapter 27 Solutions
General Physics, 2nd Edition
Ch. 27 - Prob. 1RQCh. 27 - Prob. 2RQCh. 27 - Prob. 3RQCh. 27 - Prob. 4RQCh. 27 - Prob. 5RQCh. 27 - Prob. 6RQCh. 27 - Prob. 7RQCh. 27 - Prob. 8RQCh. 27 - Prob. 9RQCh. 27 - Prob. 10RQ
Ch. 27 - Prob. 1ECh. 27 - Prob. 2ECh. 27 - Prob. 3ECh. 27 - Prob. 4ECh. 27 - Prob. 5ECh. 27 - Prob. 6ECh. 27 - Prob. 7ECh. 27 - Prob. 8ECh. 27 - Prob. 9ECh. 27 - Prob. 10ECh. 27 - Prob. 11ECh. 27 - Prob. 12ECh. 27 - Prob. 13ECh. 27 - Prob. 14ECh. 27 - Prob. 15ECh. 27 - Prob. 16ECh. 27 - Prob. 17ECh. 27 - Prob. 18ECh. 27 - Prob. 19ECh. 27 - Prob. 20ECh. 27 - Prob. 21ECh. 27 - Prob. 22ECh. 27 - Prob. 23ECh. 27 - Prob. 24ECh. 27 - Prob. 25ECh. 27 - Prob. 26ECh. 27 - Prob. 27ECh. 27 - Prob. 28ECh. 27 - Prob. 29ECh. 27 - Prob. 30ECh. 27 - Prob. 31ECh. 27 - Prob. 32ECh. 27 - Prob. 33ECh. 27 - Prob. 34ECh. 27 - Prob. 35ECh. 27 - Prob. 36ECh. 27 - Prob. 37ECh. 27 - Prob. 38ECh. 27 - Prob. 39ECh. 27 - Prob. 41ECh. 27 - Prob. 42ECh. 27 - Prob. 43ECh. 27 - Prob. 44ECh. 27 - Prob. 45ECh. 27 - Prob. 46ECh. 27 - Prob. 47ECh. 27 - Prob. 48E
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- Electrons with an energy of 0.610 eV are incident on a double slit in which the two slits are separated by 40.0 nm. (a) What is the speed of these electrons? m/s (b) What is the de Broglie wavelength (in nanometers!) of these electrons? nm (c) What is the angle between the two second-order maxima in the resulting interference pattern?arrow_forward(a) The de Broglie wavelength of an electron is 85 Å. Determine the electron energy (eV), momentum, and velocity. (b) An electron is moving with a velocity of 8 x 10° cm/s. Determine the electron energy (eV), momentum, and de Broglie wave- length (in Å).arrow_forwardThe resolving power of a microscope depends on the wavelength used. If you wanted to "see" an atom, a wavelength of approximately 1.00 x 10-11 m would be required.If electrons are used (in an electron microscope), what minimum kinetic energy is required for the electrons?arrow_forward
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