General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 27, Problem 1E
To determine
The distance of closest approach between alpha particle and the gold nucleus.
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Each a particle in a beam of a particles has a
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particles in order that they would have enough
energy so that if one is fired head-on at a gold
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the center of the nucleus?
In a Rutherford scattering experiment, an a-particle (charge = +2e) heads directly toward a gold nucleus (charge = +79e). The α-particle had a kinetic energy of 5.0 MeV when very far (r→ ∞) from the nucleus. Assuming the gold nucleus to be fixed in space, determine the distance of closest approach. Hint: Use conservation of energy with PE =kq1q2/r.
Use the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron).
Neutron: m = 1.67493x10-27 kg = 1.008665 u = 939.57 MeV/c²
.
¹H: mH = 1.67353x10-27 kg = 1.007825 u = 938.78 MeV/c²
1
1 u = 1.6605x10-27 kg = 931.5 MeV/c²
.
Consider the following decay: 239 Pu 235 U+ a. 239 Pu has a mass of 239.0521634 u, 235 U has a mass of 235.0439299 u, and a has a mass of 4.002603 u.
94
92
94
92
Determine the disintegration energy (Q-value) in MeV.
Q =
Determine the binding energy (in MeV) for 239 Pu.
94
EB =
Chapter 27 Solutions
General Physics, 2nd Edition
Ch. 27 - Prob. 1RQCh. 27 - Prob. 2RQCh. 27 - Prob. 3RQCh. 27 - Prob. 4RQCh. 27 - Prob. 5RQCh. 27 - Prob. 6RQCh. 27 - Prob. 7RQCh. 27 - Prob. 8RQCh. 27 - Prob. 9RQCh. 27 - Prob. 10RQ
Ch. 27 - Prob. 1ECh. 27 - Prob. 2ECh. 27 - Prob. 3ECh. 27 - Prob. 4ECh. 27 - Prob. 5ECh. 27 - Prob. 6ECh. 27 - Prob. 7ECh. 27 - Prob. 8ECh. 27 - Prob. 9ECh. 27 - Prob. 10ECh. 27 - Prob. 11ECh. 27 - Prob. 12ECh. 27 - Prob. 13ECh. 27 - Prob. 14ECh. 27 - Prob. 15ECh. 27 - Prob. 16ECh. 27 - Prob. 17ECh. 27 - Prob. 18ECh. 27 - Prob. 19ECh. 27 - Prob. 20ECh. 27 - Prob. 21ECh. 27 - Prob. 22ECh. 27 - Prob. 23ECh. 27 - Prob. 24ECh. 27 - Prob. 25ECh. 27 - Prob. 26ECh. 27 - Prob. 27ECh. 27 - Prob. 28ECh. 27 - Prob. 29ECh. 27 - Prob. 30ECh. 27 - Prob. 31ECh. 27 - Prob. 32ECh. 27 - Prob. 33ECh. 27 - Prob. 34ECh. 27 - Prob. 35ECh. 27 - Prob. 36ECh. 27 - Prob. 37ECh. 27 - Prob. 38ECh. 27 - Prob. 39ECh. 27 - Prob. 41ECh. 27 - Prob. 42ECh. 27 - Prob. 43ECh. 27 - Prob. 44ECh. 27 - Prob. 45ECh. 27 - Prob. 46ECh. 27 - Prob. 47ECh. 27 - Prob. 48E
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- Use the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m,= 1.67493x1027 kg= 1.008665 u = 939.57 MeVIC H: my = 1.67353x10 27 kg = 1.007825 u = 938.78 MeVic 1u= 1.6605x10-27 kg = 931.5 MeVic? Consider the following decay: 211 At 207 Bi + a. 211 At has a mass of 210.9874963 u, 207 Bi has a mass of 206.981593 u, and a has a mass of 4.002603 u. 85 83 85 83 Determine the disintegration energy (Q-value) in MeV. Determine the binding energy (in MeV) for 211 At. 85 EB =arrow_forwardA lithium ion Lit++ (Z = 3, A = 6g/mol) with incident kinetic energy EK = 7.5MEV is scattered on a gold nucleus (Z = 79, A = 197g/mol) through an angle of 10°. Assume that the mass of the lithium ion is much smaller than the mass of the gold nucleus. Please answer the following questions: %3D (a) Calculate the impact parameter b; (b) Calculate the closest approach rmin-arrow_forwardA charged particle with initial kinetic energy of 80.3 keV ionizes an electron in the K shell of a silver atom. The binding energy for K-shell electrons in silver is 25.5 keV. The charged particle has kinetic energy of 43.7 keV after the interaction. What is the kinetic energy of the secondary electron, after it is ejected from the silver atom?arrow_forward
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