General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 27, Problem 36E
To determine
The quantum number associated with earth orbital.
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The quantum state of an electron in an atom is described by quantum numbers n = 6, ℓ = 4, and mℓ = 1. The orbital total angular momentum of the electron is measured to be x × h/2π, where h is Planck’s constant. What is the number x(remember to use the scientific notation)?
What is the orbital radius of the n = 3 excited state in the Bohr model of the hydrogen atom in nanometers? The ground-state radius of the hydrogen atom is 0.529 × 10-10 m. Please give your answer with 3 decimal places.
The quantum state of an electron in an atom is described by quantum numbers n = 6, ℓ = 5, and mℓ = 2. The z-component orbital angular momentum of the electron is measured to be x × h/2π, where h is Planck’s constant. What is the number x (remember to use the scientific notation)?
Chapter 27 Solutions
General Physics, 2nd Edition
Ch. 27 - Prob. 1RQCh. 27 - Prob. 2RQCh. 27 - Prob. 3RQCh. 27 - Prob. 4RQCh. 27 - Prob. 5RQCh. 27 - Prob. 6RQCh. 27 - Prob. 7RQCh. 27 - Prob. 8RQCh. 27 - Prob. 9RQCh. 27 - Prob. 10RQ
Ch. 27 - Prob. 1ECh. 27 - Prob. 2ECh. 27 - Prob. 3ECh. 27 - Prob. 4ECh. 27 - Prob. 5ECh. 27 - Prob. 6ECh. 27 - Prob. 7ECh. 27 - Prob. 8ECh. 27 - Prob. 9ECh. 27 - Prob. 10ECh. 27 - Prob. 11ECh. 27 - Prob. 12ECh. 27 - Prob. 13ECh. 27 - Prob. 14ECh. 27 - Prob. 15ECh. 27 - Prob. 16ECh. 27 - Prob. 17ECh. 27 - Prob. 18ECh. 27 - Prob. 19ECh. 27 - Prob. 20ECh. 27 - Prob. 21ECh. 27 - Prob. 22ECh. 27 - Prob. 23ECh. 27 - Prob. 24ECh. 27 - Prob. 25ECh. 27 - Prob. 26ECh. 27 - Prob. 27ECh. 27 - Prob. 28ECh. 27 - Prob. 29ECh. 27 - Prob. 30ECh. 27 - Prob. 31ECh. 27 - Prob. 32ECh. 27 - Prob. 33ECh. 27 - Prob. 34ECh. 27 - Prob. 35ECh. 27 - Prob. 36ECh. 27 - Prob. 37ECh. 27 - Prob. 38ECh. 27 - Prob. 39ECh. 27 - Prob. 41ECh. 27 - Prob. 42ECh. 27 - Prob. 43ECh. 27 - Prob. 44ECh. 27 - Prob. 45ECh. 27 - Prob. 46ECh. 27 - Prob. 47ECh. 27 - Prob. 48E
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- Derive an expression for the ratio of X-ray photon frequency for two elements with atomic numbers Z1 and Z2.arrow_forwardFor an electron in a hydrogen atom in the n=2 state, compute: (a) the angular momentum; (b) the kinetic energy; (c) the potential energy; and (d) the total energy.arrow_forward79. a) Assume an electron in the ground state of the hydrogen atom moves at an average speed of 5.00×106 m/s. If the speed is known to an uncertainty of 1 percent, what is the minimum uncertainty in its position?The radius of the hydrogen atom in the ground state is 5.29×10−11 m. The mass of an electron is 9.1094×10−31 kg. (b) A 0.16−kg baseball thrown at 100 mph has a momentum of 7.2 kg·m/s. If the uncertainty in measuring the mass is 1.0×10^−7 of the mass, calculate the uncertainty in the baseball's position.arrow_forward
- Calculate the angular momentum of the Moon due to its orbital motion about Earth. In your calculation use 3.84 x 108 m as the average Earth–Moon distance and 2.36 x 106 s as the period of the Moon in its orbit. (b) If the angular momentum of the Moon obeys Bohr’s quantization rule (L = n h), determine the value of the quantum number n. (c) By what fraction would the Earth–Moon radius have to be increased to increase the quantum number by 1?arrow_forwardA) By what factor is the uncertainty of the electron's position(1.36×10-4 m) larger than the diameter of the hydrogen atom?(Assume the diameter of the hydrogen atom is 1.00×10-8 cm.) B) Use the Heisenberg uncertainty principle to calculate Δx for a ball (mass = 122 g, diameter = 8.50 cm) with Δv = 0.425 m/s. C) The uncertainty of the (above) ball's position is equal to what factor times the diameter of the ball?arrow_forwardAn electron is orbiting around a nucleus in a hydrogen atom in Bohr 's model with kinetic energy of 8.64✕10-20 J. Determine the allowed orbit in this atom.arrow_forward
- Considering the Bohr’s model, given that an electron is initially located at the ground state (n=1n=1) and it absorbs energy to jump to a particular energy level (n=nxn=nx). If the difference of the radius between the new energy level and the ground state is rnx−r1=5.247×10−9rnx−r1=5.247×10−9, determine nxnx and calculate how much energy is absorbed by the electron to jump to n=nxn=nx from n=1n=1. A. nx=9nx=9; absorbed energy is 13.4321 eV B. nx=10nx=10; absorbed energy is 13.464 eV C. nx=8nx=8; absorbed energy is 13.3875 eV D. nx=20nx=20; absorbed energy is 13.566 eV E. nx=6nx=6; absorbed energy is 13.22 eV F. nx=2nx=2; absorbed energy is 10.2 eV G. nx=12nx=12; absorbed energy is 13.506 eV H. nx=7nx=7; absorbed energy is 13.322 eVarrow_forwardThe electron of a hydrogen atom is in an orbit with radius of 8.46 Å (1 Å = 10-10 m), according to the Bohr model. Which of the following statements is correct? a) The total energy of the orbit is –13.6 eV, and the kinetic energy is +13.6 eV. b) The total energy of the orbit is –0.85 eV, and the potential energy is –1.70 eV. c) The total energy of the orbit is –0.85 eV, and the potential energy is +1.70 eV. d) The total energy of the orbit is –0.85 eV, and the potential energy is –0.85 eV. e) The total energy of the orbit is –3.40 eV, and the potential energy is –6.80 eV.arrow_forwardAn electron is in the nth Bohr orbit of the hydrogen atom. (a) Show that the period of the electron is T = n3t0 and determine the numerical value of t0. (b) On average, an electron remains in the n = 2 orbit for approximately 10 ms before it jumps down to the n = 1 (ground-state) orbit. How many revolutions does the electron make in the excited state? (c) Define the period of one revolution as an electron year, analogous to an Earth year being the period of the Earth’s motion around the Sun. Explain whether we should think of the electron in the n = 2 orbit as “living for a long time.”arrow_forward
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