Short Answer 4. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one that res in an ebony body (ee). You cross two flies that are heterozygous for both traits (CcEe), and find 352 flies progeny in the next generation with the following phenotypes: wild type - 193 wild type wings, ebony body - 69 You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this cross to test the null hypothesis. A) Show at least the following parts of your work: the expected vs. observed numbers for each phenotype, and the final X² value. Observed Expected (o-e)2²/e wild type body, curly wings - 64 curly wings, ebony body - 26 Edit View Insert Format V Tools Table 12pt ✓ Paragraph B IU X² Av 2 v T² v مي A D D₂

Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter12: Mendel, Genes, And Inheritance
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Short Answer 4. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one
in an ebony body (ee). You cross two flies that are heterozygous for both traits (CcEe), and find 352 flies progeny in the
next generation with the following phenotypes:
wild type - 193
wild type wings, ebony body - 69
You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this
cross to test the null hypothesis.
A) Show at least the following parts of your work: the expected vs. observed numbers for each phenotype, and the final X²
value.
Observed Expected (o-e)²/e
wild type body, curly wings - 64
curly wings, ebony body - 26
Edit View Insert Format Tools
12pt ✓ Paragraph
Table
X²
U AV T² v
BIUA
V
V
QV
G✓
⠀
Transcribed Image Text:Short Answer 4. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one in an ebony body (ee). You cross two flies that are heterozygous for both traits (CcEe), and find 352 flies progeny in the next generation with the following phenotypes: wild type - 193 wild type wings, ebony body - 69 You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this cross to test the null hypothesis. A) Show at least the following parts of your work: the expected vs. observed numbers for each phenotype, and the final X² value. Observed Expected (o-e)²/e wild type body, curly wings - 64 curly wings, ebony body - 26 Edit View Insert Format Tools 12pt ✓ Paragraph Table X² U AV T² v BIUA V V QV G✓ ⠀
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