(a) Interpretation: The position of protons bonded to the s p 2 hybridized carbons (absorbs in the 1 H NMR spectrum) in the 1 H NMR spectrum of given compound is to be estimated. Concept introduction: The protons present on s p 2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5 − 8 ppm . The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5 − 6 ppm .

Question

draw the strucutre based off the IR spectrum, 1H NMR spectrum, and 13C NMR spectrum for this compound. This compound is an ester that is commonly used as food additive to give foods and beverages a fruity flavor. Its molecular formula is C7H14O2

Answer 1

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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draw the strucutre based off the IR spectrum, 1H NMR spectrum, and 13C NMR spectrum for this compound. This compound is an ester that is commonly used as food additive to give foods and beverages a fruity flavor. Its molecular formula is C7H14O2

A B. C. H. CH Br HC-C-CH CHy CH3-C-CH H-C-CH,CH, CH CH, Which of the following compounds give four major peaks in their 1H NMR spectra? OA and B. Band C. A and C. O All of them

Identify the carbon atoms that give rise to the signals in the 1°C NMR spectrum of each compound. a. CH;CH,CH,CH,OH; 1°C NMR: 14, 19, 35, and 62 ppm b. (CHa)2CHCHO; 1°C NMR: 16, 41, and 205 ppm c. CH2 = CHCH(OH)CH3; 1C NMR: 23, 69, 113, and 143 ppm

Answer 2

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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Answer 3

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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Answer 4

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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Answer 5

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 6

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 7

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 8

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 9

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 10

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 11

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 12

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Answer 23

Ch. 17 - Prob. 17.1P Ch. 17 - Problem 17.2 What orbitals are used to form the...Ch. 17 - Problem-17.3. Give the IUPAC name for each...Ch. 17 - Prob. 17.4P Ch. 17 - Problem-17.5 What is the structure of propofol,...Ch. 17 - Problem 17.6 What is the structure of a compound...Ch. 17 - Problem 17.7 How many NMR signals does each...Ch. 17 - Prob. 17.8P Ch. 17 - Prob. 17.9P Ch. 17 - Prob. 17.10P

Solution Summary: The author explains that the position of protons bonded to the sp2 hybridized carbons is to be estimated.

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Chapter 17 Solutions