Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 7, Problem 7.2P
Interpretation Introduction
Interpretation:
The percentages of axial and equatorial conformations present in one mole of methyl- cyclohexane at
Concept introduction:
The conformation of cyclohexane is a type of
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From studies of the dipole moment of 1,2-dichloroethane in the gas phase at room temperature (25°C), it is estimated that the ratio of molecules in the anti conformation to gauche conformation is 7.6 to 1. Calculate the difference in Gibbs free energy between these two conformations.
When cyclohexane is substituted by an ethynyl group, -C=CH, the energy difference
between axial and equatorial conformations is only 1.7 kJ (0.41 kcal)/mol. Compare the
conformational equilibrium for methylcyclohexane with that for ethynylcyclohexane and
account for the difference between the two.
sketch the various conformational isomers of 1,3-dimethylcyclohexane. Indicate the position (axial/equatorial) of each of the methyl groups in each structure.
Chapter 7 Solutions
Organic Chemistry
Ch. 7 - Prob. 7.1PCh. 7 - Prob. 7.2PCh. 7 - Prob. 7.3PCh. 7 - Prob. 7.4PCh. 7 - Prob. 7.5PCh. 7 - Prob. 7.6PCh. 7 - Prob. 7.7PCh. 7 - Prob. 7.8PCh. 7 - Prob. 7.9PCh. 7 - Prob. 7.10P
Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - Prob. 7.13PCh. 7 - Prob. 7.14PCh. 7 - Prob. 7.15PCh. 7 - Prob. 7.16PCh. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Prob. 7.22PCh. 7 - Prob. 7.23PCh. 7 - Prob. 7.24PCh. 7 - Prob. 7.25PCh. 7 - Prob. 7.26PCh. 7 - Prob. 7.27PCh. 7 - Prob. 7.28PCh. 7 - Prob. 7.29PCh. 7 - Prob. 7.30PCh. 7 - Prob. 7.31PCh. 7 - Prob. 7.32PCh. 7 - Prob. 7.33PCh. 7 - Prob. 7.34APCh. 7 - Prob. 7.35APCh. 7 - Prob. 7.36APCh. 7 - Prob. 7.37APCh. 7 - Prob. 7.38APCh. 7 - Prob. 7.39APCh. 7 - Prob. 7.40APCh. 7 - Prob. 7.41APCh. 7 - Prob. 7.42APCh. 7 - Prob. 7.43APCh. 7 - Prob. 7.44APCh. 7 - Prob. 7.45APCh. 7 - Prob. 7.46APCh. 7 - Prob. 7.47APCh. 7 - Prob. 7.48APCh. 7 - Prob. 7.49APCh. 7 - Prob. 7.50APCh. 7 - Prob. 7.51APCh. 7 - Prob. 7.52APCh. 7 - Prob. 7.53APCh. 7 - Prob. 7.54APCh. 7 - Prob. 7.55APCh. 7 - Prob. 7.56APCh. 7 - Prob. 7.57APCh. 7 - Prob. 7.58APCh. 7 - Prob. 7.59APCh. 7 - Prob. 7.60APCh. 7 - Prob. 7.61APCh. 7 - Prob. 7.62APCh. 7 - Prob. 7.63APCh. 7 - Prob. 7.64APCh. 7 - Prob. 7.65APCh. 7 - Prob. 7.66APCh. 7 - Prob. 7.67APCh. 7 - Prob. 7.68APCh. 7 - Prob. 7.69APCh. 7 - Prob. 7.70APCh. 7 - Prob. 7.71APCh. 7 - Prob. 7.72APCh. 7 - Prob. 7.73APCh. 7 - Prob. 7.74APCh. 7 - Prob. 7.75AP
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- A structure with the formula C7H14O must be drawn that contains one stereocenter, an alcohol, and a disubstituted alkene including what the IUPAC name is for this compound. Dashes/wedges should be used to show which enantiomer is being drawn. In addition, what is the enantiomer drawing and IUPAC name of this compound, as well as the diastereomer of this compound and IUPAC name?arrow_forwardWrite a conformational structure for 1,2,3-trimethylcyclohexane in which all the methyl groups are axial and then show its more stable conformation.arrow_forwardGiven that the free energy of the twist-boat conformer of cyclohexane is 5.3 kcal/mol greater than that of the chair conformer, calculate the percentage of twist-boat conformers present in a sample of cyclohexane at 25 °C. Does your answer agree with the statement made in Section 3.13 about the relative number of molecules in these two conformations?arrow_forward
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- Show that the addition of each CH2 unit to an alcohol molecule changes the heat of combustion by: 2(C-H)+1(C-C)+1.5(O=O) – [2(C=O)+2(O-H)]arrow_forward5B In the following reactions, mixtures of alkenes and ethyl ethers are formed. Draw their structures. Explain which is or are likely to be the main product(s) in each reaction. In case of formation of two isomers of alkenes, explain which is formed in greater proportion CH3 CH3 H3C-C H -Br CH3 EtOHarrow_forwardDraw a structural formula for the alkene you would use to prepare the alcohol shown by hydroboration/oxidation. -CHCH3 ОН • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one.arrow_forward
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