Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 11, Problem 11.63AP
Interpretation Introduction
Interpretation:
The compounds
Concept introduction:
When an allylic alcohol is reacted with enantiomeric tartrate esters,
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Compound A has the formula C₂H₁9Cl. B is a C₂H19Br compound.
A and B undergo base-promoted E2 elimination to give the same alkene C as the major product as well as different minor products.
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Addition of HCI to C yields A as the major product.
Propose structures for A and B.
• Do not use stereobonds in your answer.
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Treatment of a hydrocarbon A (molecular formula C9H18) with Br2 in the presence of light forms alkyl halides B and C, both having molecular formula C9H17Br. Reaction of either B or C with KOC(CH3)3 forms compound D (C9H16) as the major product. Ozonolysis of D forms cyclohexanone and acetone. Identify the structures of A–D.
Compound A has molecular formula C7H15B.. Treatment of compound A with sodium ethoxide yields only one elimination product
(compound B) and no substitution products. When compound B is treated with dilute sulfuric acid, compound C is obtained, which
has molecular formula C7H160. Draw the structures of compounds A, B, and C.
Chapter 11 Solutions
Organic Chemistry
Ch. 11 - Prob. 11.1PCh. 11 - Prob. 11.2PCh. 11 - Prob. 11.3PCh. 11 - Prob. 11.4PCh. 11 - Prob. 11.5PCh. 11 - Prob. 11.6PCh. 11 - Prob. 11.7PCh. 11 - Prob. 11.8PCh. 11 - Prob. 11.9PCh. 11 - Prob. 11.10P
Ch. 11 - Prob. 11.11PCh. 11 - Prob. 11.12PCh. 11 - Prob. 11.13PCh. 11 - Prob. 11.14PCh. 11 - Prob. 11.15PCh. 11 - Prob. 11.16PCh. 11 - Prob. 11.17PCh. 11 - Prob. 11.18PCh. 11 - Prob. 11.19PCh. 11 - Prob. 11.20PCh. 11 - Prob. 11.21PCh. 11 - Prob. 11.22PCh. 11 - Prob. 11.23PCh. 11 - Prob. 11.24PCh. 11 - Prob. 11.25PCh. 11 - Prob. 11.26PCh. 11 - Prob. 11.27PCh. 11 - Prob. 11.28PCh. 11 - Prob. 11.29PCh. 11 - Prob. 11.30PCh. 11 - Prob. 11.31PCh. 11 - Prob. 11.32PCh. 11 - Prob. 11.33PCh. 11 - Prob. 11.34PCh. 11 - Prob. 11.35PCh. 11 - Prob. 11.36PCh. 11 - Prob. 11.37PCh. 11 - Prob. 11.38PCh. 11 - Prob. 11.39PCh. 11 - Prob. 11.40PCh. 11 - Prob. 11.41PCh. 11 - Prob. 11.42PCh. 11 - Prob. 11.43PCh. 11 - Prob. 11.44APCh. 11 - Prob. 11.45APCh. 11 - Prob. 11.46APCh. 11 - Prob. 11.47APCh. 11 - Prob. 11.48APCh. 11 - Prob. 11.49APCh. 11 - Prob. 11.50APCh. 11 - Prob. 11.51APCh. 11 - Prob. 11.52APCh. 11 - Prob. 11.53APCh. 11 - Prob. 11.54APCh. 11 - Prob. 11.55APCh. 11 - Prob. 11.56APCh. 11 - Prob. 11.57APCh. 11 - Prob. 11.58APCh. 11 - Prob. 11.59APCh. 11 - Prob. 11.60APCh. 11 - Prob. 11.61APCh. 11 - Prob. 11.62APCh. 11 - Prob. 11.63APCh. 11 - Prob. 11.64APCh. 11 - Prob. 11.65APCh. 11 - Prob. 11.66APCh. 11 - Prob. 11.67APCh. 11 - Prob. 11.68APCh. 11 - Prob. 11.69APCh. 11 - Prob. 11.70APCh. 11 - Prob. 11.71APCh. 11 - Prob. 11.72APCh. 11 - Prob. 11.73APCh. 11 - Prob. 11.74APCh. 11 - Prob. 11.75APCh. 11 - Prob. 11.76APCh. 11 - Prob. 11.77APCh. 11 - Prob. 11.78APCh. 11 - Prob. 11.79APCh. 11 - Prob. 11.80APCh. 11 - Prob. 11.81AP
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- An achiral hydrocarbon A of molecular formula C7H12 reacts with two equivalents of H2 in the presence of Pd-C to form CH3CH2CH2CH2CH(CH3)2. One oxidative cleavage product formed by the treatment of A with O3 is CH3COOH. Reaction of A with H2 and Lindlar catalyst forms B, and reaction of A with Na, NH3 forms C. Identify compounds A, B, and C. Be sure to answer all parts.arrow_forward(S)-2-butanol reacts with potassium dichromate (K2CrO4) in aqueous sulfuric acid to give A(C,HgO). Treatment of A with ethylmagnesium bromide in anhydrous ether gives B(C,H140). Draw the structure of B.arrow_forwardA certain compound of molecular formula C19H38 was isolated from fish oil and from plankton. On hydrogenation it gave 2,6,10,14-tetramethylpentadecane. Ozonolysis gave (CH3)2C O and a 16-carbon aldehyde. What is the structure of the natural product? What is the structure of the aldehyde?arrow_forward
- Treatment of compound A (C8H17Br) with NaOCH2CH3 affords two constitutional isomers B and C. Ozonolysis of B affords CH2=O and (CH3CH2CH2)2C=O. Ozonolysis of C affords CH3CH2CH2COCH3 and CH3CH2CHO. What is the structure of A?arrow_forwardIn the following sequence of reactions which products are identified correctly? Compound A (C 7H 11B1) is treated with magnesium in ether to give B (C 7H 11MgBr), which reacts violently with D 20 to give 1-methylcyclohexene B with acetone (CH 3COCH 3) followed by hydrolysis gives D (C 10H 180). Heating D with with a deuterium atom on the methyl group C. Reaction concentrated H 2SO 4 gives E (C 10H 16), which decolorizes two equivalents of Br 2 to give F (C 10H 16Br 2). E undergoes hydrogenation with excess H 2 and a Pt catalyst to give isobutylcyclohexane. O The correct structure of C is OH O The correct structure of D is O The correct structure of C is Br OI The correct structure of F is 8rarrow_forwardCompound W has molecular formula C₁4H18 and reacts with H₂ to form X. Oxidative cleavage of W with O3 followed by CH3 SCH3 affords Y. What is the structure of W?arrow_forward
- Sharpless epoxidation of allylic alcohol X forms compound Y. Treatment of Y with NaOH and C6H5SH in an alcohol–water mixture forms Z. Identify the structure of Y and draw a mechanism for the conversion of Y to Z. Account for the stereochemistry of the stereogenic centers in Z. Z has been used as an intermediate in the synthesis of chiral carbohydrates.arrow_forwardCompound A, C₁1 H160, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a Pd/C catalyst. On treatment of A with dilute H₂SO4, dehydration occurred and an optically inactive alkene B, C₁₁H₁4 was produced as the major product. Alkene B, on ozonolysis, gave two products. Product C, C7H6O, was shown to be an aldehyde while product D, C4H8O, was shown to be a ketone. Draw the structure of compound C. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one.arrow_forwardCompound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr) which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (Ch3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which reacts with 2 equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and Pt catalyst to give 2-methylpropylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.arrow_forward
- Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2 SO4 gives E (C10 H16), which decolorizes two equivalents of Br2 to give F (C10H16 Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to give isobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.arrow_forwardWhen A is reacted with hot aqueous NaOH, a compound B of molecular formula C8H11NO is produced. With this information, write the correct structure of B and propose the reaction mechanism (step by step, with the correct use of arrows) to obtain B.arrow_forwardCompound A, C11H16O, was found to be an optically active alcohol. Despite its apparent unsaturation, no hydrogen was absorbed on catalytic reduction over a Pd/C catalyst. On treatment of A with dilute H2SO4, dehydration occurred and an optically inactive alkene B, C11H14 was produced as the major product. Alkene B, on ozonolysis, gave two products. Product C, C8H8O, was shown to be a methyl ketone while product D, C3H6O, was shown to be an aldehyde.arrow_forward
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