Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
9th Edition
ISBN: 9781259989452
Author: Hayt
Publisher: Mcgraw Hill Publishers
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 11, Problem 46E
(a)
To determine
Find the complex power in polar form and power factor for the given power triangle.
(b)
To determine
Find the complex power in polar form and power factor for the given power triangle.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
QUESTION 10
Determine the magnitude of the current through the capacitor in the circuit below.
VT = 97V RMS, ZT = 102 , R1 = 90, Xc = 60
Enter your answer in amps but do not enter the unit. Round your answer to one decimal place.
L1
R1
C1
R2
A capacitor drawing 4 kvar is placed in parallel with the electro-magnet that draws 3 kW of active power and 4 kvar of reactive power.. a. Calculate the new value of apparent power b. What is the new value of reactive power? c. What is the value of active power? d. What is the new power factor?
Calculate the frequency of the given circuit if a constant 5V source is being used as a supply voltage and the inductive reactance is equal to 47.49 Q. The inductor has a value of 185 mH
and the resistor has a value of 2025 Q.
Note:
Express your answer in Hz and in 2 decimal places.
No need to include the unit.
V₁
+
7
Chapter 11 Solutions
Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
Ch. 11.1 - A current source of 12 cos 2000t A, a 200 ....Ch. 11.2 - Given the phasor voltage across an impedance ,...Ch. 11.2 - Prob. 3PCh. 11.2 - Prob. 4PCh. 11.2 - A voltage source vs is connected across a 4...Ch. 11.3 - If the 30 mH inductor of Example 11.7 is replaced...Ch. 11.4 - Calculate the effective value of each of the...Ch. 11.5 - For the circuit of Fig. 11.16, determine the power...Ch. 11.6 - Prob. 10PCh. 11 - Prob. 1E
Ch. 11 - Determine the power absorbed at t = 1.5 ms by each...Ch. 11 - Calculate the power absorbed at t = 0, t = 0+, and...Ch. 11 - Three elements are connected in parallel: a 1 k...Ch. 11 - Let is = 4u(t) A in the circuit of Fig. 11.28. (a)...Ch. 11 - Prob. 6ECh. 11 - Assuming no transients are present, calculate the...Ch. 11 - Prob. 8ECh. 11 - Prob. 9ECh. 11 - Prob. 10ECh. 11 - The phasor current I=915mA (corresponding to a...Ch. 11 - A phasor voltage V=10045V (the sinusoid operates...Ch. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Find the average power for each element in the...Ch. 11 - (a) Calculate the average power absorbed by each...Ch. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - The circuit in Fig. 11.36 has a series resistance...Ch. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 30ECh. 11 - Prob. 31ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - (a) Calculate both the average and rms values of...Ch. 11 - Prob. 35ECh. 11 - FIGURE 11.43 Calculate the power factor of the...Ch. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - Prob. 42ECh. 11 - Prob. 43ECh. 11 - Compute the complex power S (in polar form) drawn...Ch. 11 - Calculate the apparent power, power factor, and...Ch. 11 - Prob. 46ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - FIGURE 11.49 Instead of including a capacitor as...Ch. 11 - Prob. 54ECh. 11 - A load is drawing 10 A rms when connected to a...Ch. 11 - For the circuit of Fig. 11.50, assume the source...Ch. 11 - Prob. 57ECh. 11 - A source 45 sin 32t V is connected in series with...Ch. 11 - Prob. 60ECh. 11 - FIGURE 11.51 The circuit in Fig. 11.51 uses a Pi...Ch. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - You would like to maximize power transfer to a 50 ...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Given the complex numbers A1=630 and A2=4+j5, (a) convert A1 to rectangular form: (b) convert A2 to polar and exponential form: (c) calculate A3=(A1+A2), giving your answer in polar form: (d) calculate A4=A1A2, giving your answer in rectangular form: (e) calculate A5=A1/(A2*) giving your answer in exponential form.arrow_forwardBased on Figure Q1(a), identify the equivalent inductance seen at the terminal of a and b. [4 marks] 30mH 30mH 30mH 40mH 25mHarrow_forward11:05 C d ļ G A O 图“ ぐ Ritesh Sah ... More Edit 1. Point charges ql and q2 are held in place at the (x,y) coordinates specified below. Point P is a point of interest, there is no charge at point P. Charge q1 +2.778e-9 Cat (1,1) meters. Charge q2 = +1.00e-9 Cat (5,1) meters. Point P is at (5,4) meters. Charges q1 and q2 on an xy plane. Use the methods shown in class to: • Calculate the magnitude/size of the electric field at point P due to charges q1 and q2. • Calculate the Trig Angle, measured counter-clockwise from the +x-axis in degrees, of the electric field at point P due to charges q1 and q2.arrow_forward
- 2. A resistor of 6Q and an unknown impedance coil in series draw 12 amps from a 120 volts, 60 Hz line. If the real power taken from the line is 1,152 watts, what is the coil inductance? Two spheres senarated from each other by 10 m have a chared of 0 001 Coulomh and 0 003arrow_forward5.) Calculate the inductance or capacitance in series for the impedance 502-60° ohms. Assume the frequency to be 50 Hz. Express in four decimal places.arrow_forwardHll 36 O O OD 27I011:28 Expert Q&A + For the circuit shown below, find ) The total capacitance of the circuit ii) The total charged stored in the circuit CI 4 24 V 24arrow_forward
- QUESTION 6 A motor with 15mH of inductance and an unknown internal resistance is connected to a 50V RMS 1.1kHz source. The power factor has been corrected by adding a 7231F capacitor in parallel with the motor. Determine the value of the internal resistance. (This is a trial and error question using the given answers for practice) O 100 O 1000 O 200 O 20arrow_forwardTime left 0: ↑) IZ0A 202V 6 Assuming suitable sign of the complex impedance of the inductor and the capacitor, and for I = 5 Amp, answer the following questions. Magnitude of current through the 6 ohm resistor is Amp Real power consumed by the 6 ohm resistor is Watt Magnitude of voltage across the current source is Voltarrow_forward■ Calculate the current Ic Ic Vs 1000° -j5 Ohm 8 Ohm j6 Ohmarrow_forward
- Calculate the equivalent capacitance that would connect to points "A" and "B". Answer in microFarads. Numeric entry only. No other characters or symbols. 400 µF A В 200 µF 300 µF 100 µF Type your answer. Lenovo 画 Home End Insert Delete F3 F5 F6 F7 F8 F9 F10 F11 F12 %23 & ) Backspace Numlock 4 6 7 8 E Y U P Homearrow_forward! Q Two capacitors, each with a reactance of 400 ohms are placed in parallel. What is the combined reactance? O 200 ohms @ 2 O 400 ohms 800 ohms W S Z X #3 C E D $ 4 R FL G Search or type URL > % 5 T G < (0 6 MacBook Pro B Y H & 7 N U * 00 8 J B - ( 9 K O V ) O L 4 P لاب { + 11 = ? O 11 - } ] dearrow_forwardPlease answer a, b, c, d in Q3. Thanks! Q1. An electro-magnet draws 3 kW of active power and 3 kvar of reactive power. Q2. A capacitor drawing 4 kvar is placed in parallel with the electro-magnet of Q1. Q3. If the capacitor of Q2 is replaced with one drawing 8 kvar, calculate: A. The new value of apparent power B. The new reactive power C. The new active power D. The new power factorarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning
Power System Analysis and Design (MindTap Course ...
Electrical Engineering
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:Cengage Learning
Fault Analysis in Power Systems part 1a; Author: GeneralPAC: Power System Tutorials;https://www.youtube.com/watch?v=g8itg4MOjok;License: Standard youtube license