a)
Interpretation:
The product of the reaction has to be predicted and the mechanism of the reaction has to be shown.
Concept introduction:
Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms
E1 elimination:
b)
Interpretation:
The product of the reaction has to be predicted and the mechanism of the reaction has to be shown.
Concept introduction:
Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.
E1 elimination:
Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the β-carbon atom in two steps which leads to the product as an alkene.
c)
Interpretation:
The product of the reaction has to be predicted and the mechanism of the reaction has to be shown.
Concept introduction:
Elimination reaction: An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.
E1 elimination:
Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the β-carbon atom in two steps which leads to the product as an alkene.
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Organic Chemistry
- Start from 2-methylcyclohexanol and show the steps and mechanisms for the following products. 3-methyl-cyclohexene, 1-methyl-cyclohexene, and Methylene-cyclohexane. How how all of these products were obtained FROM 2-methylcyclohexanol. Provide a description of the mechanism of each alkene product below each mechanism drawingarrow_forwardDetermine a stepwise mechanism for the following reaction that illustrates why two substitution products are formed. Explain why 1-bromohex-2-ene reacts rapidly with a weak nucleophile (CH3OH) under Syl reaction conditions, even though it is a 1° alkyl halide. 1-bromohex-2-ene Part 1: Br CH₂OH The first step in the reaction proceeds according to which mechanism? CH₂CH₂CH₂CH=CHCH₂ + CH₂OH CH₂CH₂CH₂CH: Part 2: Br CHCH₂ Draw the missing resonance contributor. OCH3 + CH3CH₂CH₂CH=CHCH₂ CH3CH₂CH₂CH=CH-CH₂ + Br Br OCH 3 H₂CH₂CH₂CH=CH₂ view structure + + Br HBr Xarrow_forwardH3C N- H₂NNH₂ H⭑ CH3 H3C IN CH3 Hydrazine reacts with 2,4-pentanedione to yield 3,5-dimethylpyrazole. Including protonations and deprotonations, the reaction takes 12 steps. Write out the mechanism on a sheet of paper and then draw the structure of the product of step 6. • You do not have to consider stereochemistry. •You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. • In an elimination step, include the structure of the leaving group, but draw it in its own sketcher. Separate structures with + signs from the drop-down menu. ? Sn th Previous Nextarrow_forward
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- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning